$25 a month :) (its too short so i hope you have a lovely day)
9514 1404 393
Answer:
- see below for a sketch
- 12 km
Step-by-step explanation:
The distance can be calculated using the Law of Cosines. The angle internal to the triangle at Q is (180°-(146° -65°)) = 99°. Then the distance PR can be found from ...
PR² = PQ² +QR² -2·PQ·QR·cos(∠PQR)
PR² = 6² +10² -2·6·10·cos(99°) ≈ 154.77
PR ≈ √154.77 ≈ 12.44 . . . . km
The distance PR is about 12 km.
The answer is EFD because the turn is counterclockwise, around point P
- Your welcome
Answer:
let one even number be N
and another even number be N(N+2)
N(N+2)=360
n^2+2n-360=0
n^2+20n-18n-360=0
value of N= -20 ,18
but -20 not accepted
smaller number 18
Step-by-step explanation:
If you would like to solve the system of equations, you can do this using the following steps:
5p - 3r = 1 /*2
8p + 6r = 4
__________
10p - 6r = 2
<span>8p + 6r = 4
</span>__________
10p - 6r + 8p + 6r = 2 + 4
18p = 6
p = 6/18
p = 1/3
<span>5p - 3r = 1
</span>5 * 1/3 - 3r = 1
5/3 - 3r = 1
5/3 - 1 = 3r
5/3 - 3/3 = 3r
2/3 = 3r
r = 2/9
(p, r) = (1/3, 2/9)
The correct result would be <span>(1/3, 2/9)</span>.
