Solution :
Given
Let the initial approximation is 
So by Newton's method, we get
are identical up to eight decimal places.
The approximate real root is x ≈ 1.32471795
∴ x = 1.32471795
0.75 as a percentage is 75%, as you move the decimal over one place.
Yes, it is. You may prove it using something like this: 1 is an integer. 1-1 is a difference between integers. A difference between integers returns an integer, so 0 is an integer.
Answer:
Statements 3, 4 and 5 are true.
Step-by-step explanation:
x^2 - 8x + 4
Using the quadratic formula:
x = [ -(-8) +/- √((-8)^2 - 4*1*4)] / 2
= (8 +/- √(64 - 16)) / 2
= 4 +/- √48 / 2
= 4 +/- 4√3/2
= 4 +/- 2√3.
So the third statement is true.
Converting to vertex form:
x^2 - 8x + 4
= (x - 4)^2 - 16 + 4
= (x - 4)^2 -12
So the extreme value is at (4, -12)
So the fourth statement is true.
The coefficient of the term in x^2 is 1 (positive) so the graph has a minimum.
There is a mistake 9,12,13 is not a right triangle. but 9,12,15 is. IF you use this triangle instead, then the area of the 13,14,15 triangle is the sum of the area of the other two triangles.
