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3 years ago

Help me which one is a linear fUnction

Mathematics

2 answers:

horsena [70]3 years ago

4 0

Answer:

Step-by-step explanation:

trapecia [35]3 years ago

4 0

Pretty sure it’s B!

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3. Why can the numerator and denominator of a rational expression be divided by their common factors? What conditions must be pl

liberstina [14]

Answer:

Step-by-step explanation:

Hello, do you agree that for any real number a (different from 0)

$\dfrac{a}{a}=1$

5/5 = 1 for instance.

So, when you have the same common factor at the numerator and at the denominator you can eliminate it. For instance.

$\dfrac{10}{4}=\dfrac{5*2}{2*2}=\dfrac{5}{2}\cdot \dfrac{2}{2}=\dfrac{5}{2}$

You just need to be careful with 0, as dividing by 0 is not allowed.

Hope this helps

Thank you.

4 0

4 years ago

Consider the given density curve.

Gemiola [76]

Answer:

11 is best answer for it ....,..........

4 0

2 years ago

109 2/3 divided by 1/2

Alexandra [31]

Answer:

$\large\boxed{219\dfrac{1}{3}}$

Step-by-step explanation:

$109\dfrac{2}{3}:\dfrac{1}{2}\\\\\text{Divide by a fraction is the same operation as multiply by its reciprocal}\\\\109\dfrac{2}{3}:\dfrac{1}{2}=109\dfrac{2}{3}\cdot\dfrac{2}{1}=109\dfrac{2}{3}\cdot2=\left(109+\dfrac{2}{3}\right)\cdot2\\\\\text{use distributive property}\\\\(109)(2)+\left(\dfrac{2}{3}\right)(2)=218+\dfrac{4}{3}=218+1\dfrac{1}{3}=219\dfrac{1}{3}$

3 0

3 years ago

baherus [9]

Answer:

3. $\overline{PM}\cong \overline{ON}$ Distances between two parallel lines $\overline{MN} \ and\ \overline{PO}$

4. $\overline{AC}$ = $\overline{CE}$ : Reason; Corresponding part of ΔACB and ΔDCE

C is the midpoint of $\overline{AE}$ : Reason; $\overline{AC}$ = $\overline{CE}$ : Definition of midpoint

Step-by-step explanation:

3. A parallelogram is defined as a quadrilateral with two opposite sides equal and parallel and having equal opposite interior angles

MNOP is a parallelogram: Reason; Given

$\overline{PM}\left | \right |\overline{ON}$ : Reason; Opposite sides of a parallelogram

∠NOM ≅ ∠OMP: Reason Alternate interior angles

$\overline{MN}\left | \right |\overline{PO}$ : Reason; Opposite sides of a parallelogram

∠NMO ≅ ∠MOP: Reason Alternate interior angles

$\overline{PM}\cong \overline{ON}$ Distances between two parallel lines $\overline{MN} \ and\ \overline{PO}$

4. $\overline{AB}\left | \right |\overline{DE}$ : Reason; Given

∠EAB ≅ ∠AED: Reason; Alternate int. ∠s Thm

∠ABC ≅ ∠EDB : Reason; Alternate int. ∠s Thm

C is the midpoint of $\overline{BD}$ : Reason; Given

$\overline{BC}$ = $\overline{CD}$ : Reason; Definition of midpoint

Therefore, ΔACB ≅ ΔDCE: Reason Angle Angle Side (AAS) Theorem

$\overline{AC}$ = $\overline{CE}$ : Reason; Corresponding part of ΔACB and ΔDCE

C is the midpoint of $\overline{AE}$ : Reason; Definition of midpoint

5 0

3 years ago

A candy company plans to hang posters of a new product in supermarkets. The product is a box of premium chocolates. The art team

Kitty [74]

Answer:

Length of the box is 8 inches while the width is 5 inches

Step-by-step explanation:

The question here says that a candy company plans to hang posters of a new product in supermarkets. The product is a box of premium chocolates. The art team made a scale drawing of the top of the box using a scale of 3 inches to 1 inch. The length of the scale drawing of the box is 24 inches, and its width is 15 inches. We are now asked to find the actual dimensions of the top of the chocolate box

Since the scale drawing measures 24 inches in length and 15 inches in width

And we need to remember that that the scale drawing to the actual dimensions of the package is 3:1

The scale drawings measure length 24 inches. This means that for every 1 inch of the candy box,3 inches scale drawing is taken.

If the scale drawing is 24,the actual length is

24/3 = 8 inches

Now do same for width which has a scale drawing of 15 inches,and it will have

15/3 = 5 inches

The length and the width of the chocolate box measures 8 inches by 5 inches

6 0

3 years ago