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3 years ago

Help me which one is a linear fUnction

Mathematics

2 answers:

horsena [70]3 years ago

4 0

Answer:

Step-by-step explanation:

trapecia [35]3 years ago

4 0

Pretty sure it’s B!

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Tell whether the angles are complementary or supplementary. Then find the value of x

skelet666 [1.2K]

Answer:

complementary

x = 55

Step-by-step explanation:

5 0

3 years ago

Four friends all use $10 off coupons to buy themselves concert tickets.

eimsori [14]

Answer:

$64

Step-by-step explanation:

Since there were 4 of them and the coupons were $10 off, they saved a total of $40

To find how much they would have spent without the coupons, add 40 to 216:

216 + 40

= 256

To find the normal cost of one ticket, divide this by 4:

256/4

= 64

So, the price of one concert ticket without the coupon is $64

5 0

3 years ago

Can someone please help me on this one

likoan [24]

You know vertical Angles SRU and TRV are congruent.

You are given that Sides UR and VR are congruent.

You are given that Angles SUT and SVT are congruent.

An appropriate choice is the ASA postulate, since you have congruent angles with congruent sides in between.

4 0

3 years ago

Solve each solution. Check your solution. -32 = -4b

statuscvo [17]

You need to divide-4 on both sides which will get you 8.hope this helps

7 0

3 years ago

Read 2 more answers

The computer that controls a bank's automatic teller machine crashes a mean of 0.6 times per day. What is the probability that,

professor190 [17]

Answer:

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Mean of 0.6 times a day

7 day week, so $\mu = 7*0.6 = 4.2$

What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-4.2}*(4.2)^{0}}{(0)!} = 0.0150$

$P(X = 1) = \frac{e^{-4.2}*(4.2)^{1}}{(1)!} = 0.0630$

$P(X = 2) = \frac{e^{-4.2}*(4.2)^{2}}{(2)!} = 0.1323$

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0150 + 0.0630 + 0.1323 = 0.2103$

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

3 0

3 years ago