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vlabodo [156]
3 years ago
6

Sal and Jen went to the store together, and each bought the same car stereo.

Mathematics
1 answer:
scZoUnD [109]3 years ago
8 0

Answer: Sal used a debit card and paid a total of $324.80 for the stereo. (I took the test too)

Step-by-step explanation: Multiply $21.30 by 18 months. Then subtract the interest, $58.60, from the product because Sal paid immediately with a card which implies using a debit card. You get $324.80.

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Help please...
stealth61 [152]

Answer:

1) 80%  2)25%

Step-by-step explanation:

1)80% of $2.50 = $4.50

2)25% of $9 = $2.25

  9 - 2.25 = $6.75

7 0
3 years ago
What is the answer to this decimal problem 0.32÷n=0.032
11111nata11111 [884]

10 because you know that the decimal moves one to the left if you are dividing by ten and one to the right if you are multiplying by ten.

Check your work. 0.32 divided by 10 is 0.032

6 0
3 years ago
Read 2 more answers
How is using partial products to find the product of two 2-digit factors similar to how you have used partial products in the pa
klasskru [66]
Well the multiplication part is the same .Its in the ordering it has to be(ex: 42 times 35) but it has to be placed vertically .For the second number multiply to the right then the left .Repeat .Then you got your answer using 2 digits similar to regular multiplication partial products .Hope this helped !!
4 0
3 years ago
Read 2 more answers
Are 8x^2y and -5yx^2 like terms? Explain.
MaRussiya [10]

Like terms must have the same variables and those variables must have the same powers.

7a^2b^3 and 9a^2b^3 are like terms, because they both have a^2 and they both have b^3.

7a^2b^3 and 7a^3b^2 are NOT like terms, because the powers no longer match.

In your example, do you have the same variables and do the variables have the same powers in both expressions?

6 0
3 years ago
Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.
frozen [14]

Note: Consider we need to find the vertices of the triangle A'B'C'

Given:

Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.

Triangle A,B,C with vertices at A(-3, 6), B(2, 9), and C(1, 1).

To find:

The vertices of the triangle A'B'C'.

Solution:

If triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C', then

(x,y)\to (y,-x)

Using this rule, we get

A(-3,6)\to A'(6,3)

B(2,9)\to B'(9,-2)

C(1,1)\to C'(1,-1)

Therefore, the vertices of A'B'C' are A'(6,3), B'(9,-2) and C'(1,-1).

7 0
3 years ago
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