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3 years ago

There are two bags containing only purple and yellow marbles.

Mathematics

1 answer:

Mashcka [7]3 years ago

4 0

In least likely to most likely:
Event 4
Event 2
Event 3
Event 1

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The rate of change (dP/dt), of the number of people on an ocean beach is modeled by a logistic differential equation. The maximu

Kazeer [188]

Answer:

$\frac{dP}{dt} = 2.4P(1 - \frac{P}{1200})$

Step-by-step explanation:

The logistic differential equation is as follows:

$\frac{dP}{dt} = rP(1 - \frac{P}{K})$

In this problem, we have that:

$K = 1200$ , which is the carring capacity of the population, that is, the maximum number of people allowed on the beach.

At 10 A.M., the number of people on the beach is 200 and is increasing at the rate of 400 per hour.

This means that $\frac{dP}{dt} = 400$ when $P = 200$ . With this, we can find r, that is, the growth rate,

$\frac{dP}{dt} = rP(1 - \frac{P}{K})$

$400 = 200r(1 - \frac{200}{1200})$

$166.67r = 400$

$r = 2.4$

So the differential equation is:

$\frac{dP}{dt} = rP(1 - \frac{P}{K})$

$\frac{dP}{dt} = 2.4P(1 - \frac{P}{1200})$

3 0

3 years ago

Solve the inequality showing all steps needed to justify your answer. State your solution in interval notation

dybincka [34]

Which two measures did the United States take to counter terrorism after the September 11 attacks?

5 0

4 years ago

70 POINTS PLZ ANSWER I NEED ASAP SHOW STEPS

Crazy boy [7]

I think it would be C?

3 0

3 years ago

Read 2 more answers

1 pt) If a parametric surface given by r1(u,v)=f(u,v)i+g(u,v)j+h(u,v)k and −4≤u≤4,−4≤v≤4, has surface area equal to 1, what is t

natta225 [31]

The area of the surface given by $\vec r_1(u,v)$ is 1. In terms of a surface integral, we have

$1=\displaystyle\int_{-4}^4\int_{-4}^4\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

By multiplying each component in $\vec r_1$ by 5, we have

$\dfrac{\partial\vec r_2(u,v)}{\partial u}=5\dfrac{\partial\vec r_1(u,v)}{\partial u}$

and the same goes for the derivative with respect to $v$ . Then the area of the surface given by $\vec r_2(u,v)$ is

$\displaystyle\int_{-4}^4\int_{-4}^425\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\boxed{25}$

8 0

3 years ago

Does anyone know how to find the side length of this square.if so then, i will mark brainlist.

kvv77 [185]

Hello!

To find the side length you use the equation

$a = \sqrt{2} \frac{d}{2}$

a is side length
d is diagonal

Put in the number we know

$a = \sqrt{2} * \frac{27}{2}$

Divide

$a = \sqrt{2} * 13.5$

Multiply

a = 19.091

The answer is 19.09

Hope this helps!

8 0

4 years ago