Assuming they work until their cost become the same, obviously.
The difference between the first charge of painter A and painter B = 376 - 280 = 96.
The hourly cost difference between painter B and painter A = 15 - 12 = 3.
So, painter A in the first hour has 96 more dollars than painter B, and as every hour pass, the difference goes down by 3 (as painter B gets 3 more dollars every hour)
Therefore, it would take 96 : 3 = 32 hours for the cost to be the same
Recheck : After 32 hours, painter A has 376 + 32 x 12 = 760 (dollars)
painter B has : 280 + 15 x 32 = 760 (dollars)
<u>Answer:</u>

<u>Step-by-step explanation:</u>
32a^3 + 12a^2
To factorize this, start by taking the common variable out. As we have two powers for the same variable a, we can take the smaller power of a as a common to get like shown below:
32a^3 + 12a^2
a^2 (32a + 12)
Now when you have taken the variable as a common, try and take out a common number from the coefficient of a as well:
a^2 (32a + 12)
4a^2 (8a + 3)
So, the fully factored form of 32a^3 + 12a^2 is 4a^2 (8a + 3).
Answer:
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Step-by-step explanation:
Because if you make a number line, -11 is way more far than -7.
So -7 is greater than -11.
If there are 4 marbles left over each time, then we can forget about them for now.
So the question is, what is the smallest number than can be divided into 6,7 and 8?
the numbers have only one non-1 divisor in common: both 6 and 8 are divisible by 3.
so for our purposes we can "delete" one 2 and ask:
what is the smallest number than can be divided into 3,7 and 8 ?
There are no more divisors in common, so we just have to multiply them: 3*7*8=21*8=168
and the 4 marbles "extra"? We add them to this sum.
the the smallest possible number in the box is 168+4=172.