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TEA [102]
4 years ago
12

Solve the inequality showing all steps needed to justify your answer. State your solution in interval notation

Mathematics
1 answer:
dybincka [34]4 years ago
5 0
<span>Which two measures did the United States take to counter terrorism after the September 11 attacks?

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Use the elimination method to solve the system of equations. Choose the correct ordered pair. 
kiruha [24]
5x+3y=58
5x-3y=22
(3y gets cancelled bc 3y-3y=0,  then add 5x with 5x, so you're left with)
10x=80, (divide both sides by 10)
x=8
Now we look for y. So choose one formula from the two (let's say 5x + 3y=58)
Substitute x for 8 so it will look like---- 5(8)+3y=58
Multiply 5*8--- so you get --  40+3y=58
Subtract 40 from both sides and you're left with 3y=18
divide both sides by 3
you get y=6
In conclusion, x=8 and y=6 hence, (8,6)


5 0
3 years ago
Read 2 more answers
Solve the questions below
Stells [14]

Answer:

4. 50.19°

5. 25.19°

Step-by-step explanation:

4. Reference angle = x°

Opposite = 6 units

Adjacent = 5 units

Thus,

tan(x) = \frac{6}{5}

tan(x) = 1.2

x = tan^{-1}(1.2)

x = 50.19 (nearest hundredth)

5. Reference angle = x°

Opposite = 48 - 5.2 = 42.8 ft

Adjacent = 91 ft

Thus,

tan(x) = \frac{42.8}{91}

tan(x) = 0.47032967

x = tan^{-1}(0.47032967)

x = 25.19 (nearest hundredth)b

7 0
3 years ago
What is the y-intercept of the function f(x) = -2/9x+1/3?
Brilliant_brown [7]

Answer:

y- intercept = \frac{1}{3}

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

f(x) = - \frac{2}{9} x + \frac{1}{3} ← is in slope- intercept form

with y- intercept c = \frac{1}{3}

7 0
4 years ago
What's the answer <br>c2+8c+7
lara [203]
Are you factoring or simplifying?
6 0
4 years ago
Read 2 more answers
Find the average value of f(x, y = over the region, r, the triangle with vertices (0, 0, (0, 1 and (1, 1.
makkiz [27]
Can't be done without knowing what f is...

But I can tell you that the average value of f is given by

\dfrac{\displaystyle\iint_Rf(x,y)\,\mathrm dx\,\mathrm dy}{\displaystyle\iint_R\mathrm dx\,\mathrm dy}

At the very least, we can compute the denominator, which is just the area of R. You have

\displaystyle\iint_R\mathrm dx\,\mathrm dy=\int_{x=0}^{x=1}\int_{y=x}^{y=1}\mathrm dy\,\mathrm dx=\int_0^1(1-x)\,\mathrm dx=\dfrac12

so the average value will be

2\displaystyle\iint_Rf(x,y)\,\mathrm dx\,\mathrm dy
4 0
4 years ago
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