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Reika [66]
3 years ago
12

18. Find the smallest angle in a triangle whose sides are of length 3x, 4x and 6x.

Mathematics
1 answer:
navik [9.2K]3 years ago
7 0

Answer:

Step-by-step explanation:

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240x is=f simplfied.

Step-by-step explanation:

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A polygon has the vertices P(-2,6), Q(4,6), R(4,1) and S(-2,1). What is the length of side RS?
inessss [21]
It is 6 units because you find the absolute value of the two different coordinates, in this case it is 4 and -2. Since they belong in different quadrants (one x or y value is positive and the other is negative) you add them. If they are both in the same quadrant, you subtract them. 
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THIS IS THE T H I R D TIME IVE POSTED THIS P L E A S E ANSWER
Goshia [24]

Find common denominators. 10 is the common denominator. Multiply 2 to numerator and denominator of -3/5

(-3/5)(2/2) = -6/10

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Isolate the x. Subtract 1/10 from both sides

x + 1/10 (-1/10) = -6/10 (-1/10)

x = -6/10 - 1/10

x = -7/10

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4 0
3 years ago
Can someone help me with this ASAP plz
jeka57 [31]

Answer: The answer would be 0=0 I think.

Step-by-step explanation:

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3 years ago
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A B C OR D PLEASE HELP !!!!!!!!!!!!!!!!!!!!!!!!!!! I REALLY APPRECIATE
ddd [48]

Answer: B


Step-by-step explanation: Okay so you add 6m and 1m to get 7m for that entire side. Then you have 3m on each side that is slanted. You finally add 5m.

7m + 3m + 3m + 5m = 18m^2


4 0
3 years ago
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