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Reika [66]
2 years ago
12

18. Find the smallest angle in a triangle whose sides are of length 3x, 4x and 6x.

Mathematics
1 answer:
navik [9.2K]2 years ago
7 0

Answer:

Step-by-step explanation:

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Please help me solve this problem with step by step explanation.​
Kisachek [45]

Answer:

Im not rally sure but maybe 5.71 , here is my explanation :

Step-by-step explanation:

Tan 55 =x/4

tan 55 = 1/42814

1/42814 = x /4

×=5.712592027 .

3 0
3 years ago
What's seven plus seven
timofeeve [1]
If you add 7+7 you will get 14
3 0
2 years ago
Read 2 more answers
Please help me branniest <br> Explain answers
Nana76 [90]

when a number is raised to two powers, the first step is to multiply the two powers together:

1/3 * 3 = 1

Now you have 5^1 which equals 5.


The answer is B. 5



7 0
3 years ago
a line that includes the point (3,4) has a slope of 2. what is the equation in the slope-intercept form?
Andreas93 [3]

Answer:

y=2x-2

Step-by-step explanation:

<em>the slope is y/x</em>

the slope is 2 or 2/1

<em>subtract 2 from the y value and 1 from the x value</em>

(3-1,4-2) = (2,2)

<em>keep doing this until you get a 0 in the x value</em>

(2-1,2-2) = (1,0)

<em>1 is your x-intercept</em>

(1-1,0-2) = (0,-2)

-2 is your y intercept.

So now you know your y-intercept and your slope so you can now write your equation.

<em>y=mx+b</em>

<em>m=slope, b=y-intercept</em>

m=2, b=-2

<em>substitute into the equation</em>

y=2x-2

8 0
3 years ago
Suppose r(t)=costi+sintj+3tk represents the position of a particle on a helix, where z is the height of the particle above the g
Ilia_Sergeevich [38]

a. The \vec k component tells you the particle's height:

3t=16\implies t=\dfrac{16}3

b. The particle's velocity is obtained by differentiating its position function:

\vec v(t)=\dfrac{\mathrm d\vec r(t)}{\mathrm dt}=-\sin t\,\vec\imath+\cos t\,\vec\jmath+3\,\vec k

so that its velocity at time t=\frac{16}3 is

\vec v\left(\dfrac{16}3\right)=-\sin\dfrac{16}3\,\vec\imath+\cos\dfrac{16}3\,\vec\jmath+3\,\vec k

c. The tangent to \vec r(t) at t=\frac{16}3 is

\vec T(t)=\vec r\left(\dfrac{16}3\right)+\vec v\left(\dfrac{16}3\right)t

4 0
3 years ago
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