All categories

2 years ago

18. Find the smallest angle in a triangle whose sides are of length 3x, 4x and 6x.

Mathematics

1 answer:

navik [9.2K]2 years ago

7 0

Answer:

Step-by-step explanation:

You might be interested in

Short Response 6. Are the triangles at the right simílar? Explain.

Taya2010 [7]

Answer:

Yes they are similar because they are both right angles but the one on the right is bigger than the one on the left.

Step-by-step explanation:

5 0

3 years ago

14 minus 48 plus 93 divided by -95

ankoles [38]

Answer:

The answer would be -35.

Step-by-step explanation: (14-48) + (93 DIVIDED BY (-95))= -34.9789473684 WHICH ROUNDS OUT TO BE -35.

7 0

3 years ago

Draw an obtuse angle big. place a point p inside the angle. now construct perpendiculars from the point to both sides of the ang

never [62]

I have drawn three obtuse angles showing three different positions.

then taken a point p inside it.

Now to draw perpendicular from a point to a given line

we draw a line parallel fom that point to that given line.

After that from that point we draw perpendicular to that line.

Now the question arises which side is closer to point p ,

The answer is if length of perpendicular from p to the line is longer that side is farther from the point p , and if the length of perpendicular is shorter then that that line is nearer to point P.

8 0

2 years ago

Simplify the expression: a. b^2+49–(b–7)^2 b. 2a+6b)^2–24ab

klemol [59]

Part a b2+49−(b−7)2

Distribute:

=b2+49+−b2+14b+−49

Combine Like Terms:

=b2+49+−b2+14b+−49

=(b2+−b2)+(14b)+(49+−49)

=14b

Answer:

=14b
part b

(2a+6b)2−24ab

Distribute:

=4a2+24ab+36b2+−24ab

Combine Like Terms:

=4a2+24ab+36b2+−24ab

=(4a2)+(24ab+−24ab)+(36b2)

=4a2+36b2

Answer:

=4a2+36b2

5 0

3 years ago

Fine the equation of the line that is perpendicular to the given line and passes through the given point. Enter the right side o

Kipish [7]

Answer:

$y=-\frac{4}{7} x+\frac{55}{7}$

Step-by-step explanation:

Change the given equation to slope-intercept to get $y=\frac{7}{4}x-\frac{1}{4}$ . When you multiply the slopes of perpendicular lines, you get -1. -1 divided by $\frac{7}{4}$ is $-\frac{4}{7}$ . The slope of the new line is then $-\frac{4}{7}$ . The perpendicular line passes through (5, 5) so you can have the equation $5=-\frac{4}{7} (5)+b$ . Simplifying gets $b = \frac{55}{7}$ . So now the final equation for the perpendicular line is $y=-\frac{4}{7} x+\frac{55}{7}$

6 0

3 years ago