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Svet_ta [14]
3 years ago
12

Solve for x.............​

Mathematics
1 answer:
Inessa [10]3 years ago
8 0

Answer:

Step-by-step explanation:

7388

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If −1 is a zero of the polynomial p(x)=ax^3−x^2+x+4, find the value of a.
vitfil [10]

Answer:

a = 2

Step-by-step explanation:

given x = - 1 is a zero then f(- 1) = 0 , that is

a(- 1)³ - (- 1)² - 1 + 4 = 0

- a - 1 - 1 + 4 = 0

- a + 2 = 0 ( subtract 2 from both sides )

- a = - 2 ( multiply both sides by - 1 )

a = 2

8 0
2 years ago
What is 2+2???????????????????????????????????
Eduardwww [97]

2 + 2 equals to 4

You can do it on the calculator too.

4 0
4 years ago
Read 2 more answers
The length of a rectangle is 5 inches less than 4 times the width. The perimeter is 110 inches. Find the length and the width.
nataly862011 [7]

Answer:

  • Length = 43 inches
  • Width = 12 inches

Step-by-step explanation:

Perimeter of a rectangle = 2 * ( L + W)

The length of a rectangle is 5 inches less than 4 times the width.

Assume the width is x. Length is:

4x - 5

Equation is therefore:

2 * (4x - 5 + x) = 110

4x - 5 + x = 110/2

5x - 5 = 55

5x = 55 + 5

x = 60/5

x = 12 inches

If width is 12 inches, then length is:

= 4x - 5

= 4 * 12 -5

= 43 inches

6 0
3 years ago
What are the domain and range of f(x) = (1/6)x + 2?
Black_prince [1.1K]
F(x)=x/6+2

There is no restriction upon the values of x, or the values of y.

So the domain and range are both the set of all real numbers.

x=(-oo, +oo) and y=(-oo, +oo)

This can be further seen by the fact that this is a line with a slope of 1/6.  So there is no restriction upon x as all values of x produce real values of y.  And y approaches -oo as x approaches -oo and y approaches +oo as x approaches +oo.
6 0
3 years ago
PLEASE HELP URGANT The vertices of a rectangle are R(–5, –5), S(–1, –5), T(–1, 1), and U(–5, 1). A translation maps R to the poi
mote1985 [20]

Answer:

translation -(-7, -4)

5 0
3 years ago
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