Three consecutive numbers have a sum of 36. What are the numbers?
1 answer:
Answer:
11,12,13
Step-by-step explanation:
x is the first number
x+1 is the second number
x+2 is the third number
x+ x+1+x+2 = 36
Combine like terms
3x+3 = 36
Subtract 3 from each side
3x+3-3= 36-3
3x = 33
Divide by 3
3x/3 = 33/3
x = 11
The numbers are 11, 11+1, 11+2
11,12,13
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