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Doss [256]
3 years ago
6

Which table(s), if any, represents a proportional relationship? Explain.

Mathematics
1 answer:
Wewaii [24]3 years ago
4 0

Answer:

The answer is Table 2.

Step-by-step explanation:

The answer is Table 2 because it has a proportional relationship. How I know it is a proportional relationship is because it said

0:0

1:10

2:20

3:30

4:40

5:50

If you look at it closely then you will see the 10 and 1's time table.

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leontyne sings for $1,000 an hour. Her rate increases by 50 percent after midnight. If she sings one night from 8:30 pm until 1:
iren2701 [21]
From 8.30 pm to 12 : 00

Difference = 12 : 00 - 08:30 = 3 : 30

3 hours 30 minutes = 3.5 hours.

Total for those hours = 3.5 * 1000 = $3500

From 12:00 to 1:00 am  = 1 hour.

50% increase =  50% of 1000 = .50 * 1000 = 500

So it will increase to 1000 + 500 = $1500 per hour.

For the 1 hour extra, 1 * 1500 = $1500

Total = $3500 + $1500 = $5000

She will be paid $5000
4 0
3 years ago
Assume the readings on thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. Find the pro
lisov135 [29]

Answer:

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

The sketch is drawn at the end.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 0°C and a standard deviation of 1.00°C.

This means that \mu = 0, \sigma = 1

Find the probability that a randomly selected thermometer reads between −2.23 and −1.69

This is the p-value of Z when X = -1.69 subtracted by the p-value of Z when X = -2.23.

X = -1.69

Z = \frac{X - \mu}{\sigma}

Z = \frac{-1.69 - 0}{1}

Z = -1.69

Z = -1.69 has a p-value of 0.0455

X = -2.23

Z = \frac{X - \mu}{\sigma}

Z = \frac{-2.23 - 0}{1}

Z = -2.23

Z = -2.23 has a p-value of 0.0129

0.0455 - 0.0129 = 0.0326

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

Sketch:

3 0
3 years ago
Please help answer !:) <br> Will give brainlst!! <br> Have a nice day
disa [49]
Photo is for answer one
2. 1000000

4 0
3 years ago
Find maclaurin series
Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}

The first 3 terms of the series are

\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}

7 0
2 years ago
A color printer prints 24 pages in 9 minutes. How many minutes does it take per page?
Gnom [1K]

Answer:

it gets almost 3 pages but it gets 2 pages per minute

Step-by-step explanation:

3 0
2 years ago
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