You have to use PEMDAS (Parentheses Exponents Multiplication/Division Addition/Subtraction) to solve this,
Because you don't have any parenthesis or exponents you start with Multiplication/Division. This means you do 4*3 to get 26+5-12
Then, you move to Addition/Subtraction in which you complete left to right, So you do 26+5 to get 31-12
Finally you subtract 31-12 to get 19
The two non negative real numbers with a sum of 64 that have the largest possible product are; 32 and 32.
<h3>How do we solve the nonnegative real numbers?</h3>
Let the two numbers be x and y.
Thus, if their sum is 64, then we have;
x + y = 64
y = 64 - x
Their product will be;
P = xy
Putting (64 - x) for y in the product equation we have;
P = (64 - x)x
P = 64x - x²
Since the product is maximum, let us find the derivative;
P'(x) = 64 - 2x
At P'(x) = 0, we have;
64 - 2x = 0
2x = 64
x = 64/2
x = 32
Thus; y = 64 - 32
y = 32
Read more about nonnegative real numbers
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To solve this you just do ehat was done to the coordinates. So x goes from x to 4x do you are mutiplying by 4. and the same goes for y. so your scale factor is 4
2 times 4 is 8 and 1 times 4 is four
A(8,4)
4 times 4 is 16 and 1 times four is four
B(16,4)
Four times four is sixteen and negitive three times four is negitive 12
C(16,-12)
<span>Given the options the answer will be B. </span>
I can tell you how to solve this problem.
You can find the areas using both the values as the radiuses (find the are of a circle).
Subtract the smaller area from the larger area and there is your answer.
Hope this helped.
Good Luck!
