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3 years ago

Can someone help me with this? I don't really understand it

Mathematics

1 answer:

SSSSS [86.1K]3 years ago

6 0

Answer:

#1 goes to B.

#2 goes to C.

#3 goes to D.

#4 goes to A.

Hope this helps.

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The weight of an object on the moon varies directly with its weight on the earth. If an object weighing 95 lbs on the moon weigh

Luda [366]

ANSWER

450lb

EXPLANATION

If the weight, m of an object on the moon varies directly as the weight of an object e, on the earth, then we can write the mathematical statement,.
$m \propto \: e$
We introduce the constant of proportionality to obtain,

$m = ke$

When, m=95, e=570,

This implies that,

$95 = 570k$
$k = \frac{95}{570}$

$k = \frac{1}{6}$

The equation now becomes,

$m = \frac{1}{6} e$

We want to find e, when m=2700,

$m = \frac{1}{6} \times 2700$

$m =450lb$

8 0

3 years ago

Which is closest to the value of w in the triangle below?

mr Goodwill [35]

Answer: B. 2.5 in

Step-by-step explanation:

From the given right angle triangle,

the hypotenuse of the right angle triangle is the unknown side.

With m∠32 as the reference angle,

the adjacent side of the right angle triangle is 4 in

the opposite side of the right angle triangle is w

To determine w, we would apply

the tangent trigonometric ratio which is expressed as

Tan θ = opposite side/adjacent side. Therefore,

Tan 32 = w/4

w = 4tan32 = 4 × 0.625

w = 2.5 in

8 0

3 years ago

Grace earns $7 for each car she washes. She always saves $25 of her weekly earnings. This week, she wants to have at least $65 i

mars1129 [50]

7c - 25 ≥ 65 is the answer.

3 0

4 years ago

Distance between parallel lines y=3x+10 and y=3x-20

Alecsey [184]

1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).

2. Use formula $d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}}$ to find the distance from point $(x_0,y_0)$ to the line Ax+By+C=0.

The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:

$d=\dfrac{|3\cdot 0-10-20|}{\sqrt{3^2+(-1)^2}}=\dfrac{30}{\sqrt{10}}=3\sqrt{10}$ .

3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.

Answer: $d=3\sqrt{10}$ .

4 0

3 years ago

Simplify the next two expressions

prisoha [69]

1. 7x-40
2. 8x-30y-10

4 0

4 years ago

Can someone help me with this? I don't really understand it​

Can someone help me with this? I don't really understand it