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wlad13 [49]
3 years ago
13

What element should I use when fighting Alatreon

Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
4 0

Answer:

Earth?

Step-by-step explanation:

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I need help with the attached​
Aleksandr-060686 [28]

Answer: super sorry! i have no idea but im sure someone else knows (:

Step-by-step explanation:

sorry

8 0
2 years ago
I have been trying to solve problem 5 and 6 for 30 mins​
jeyben [28]

Answer:

#5

x = 45

E

Step-by-step explanation:

Theorems you need:

  • The measures of 2 adjacent angles that form a straight line with the outer sides add up to 180°.
  • The sum of the interior angles of a triangle add up to 180° ((n-2)×180).

#5

Knowing those, you first want to find the triangle's 3 interior angles.

The angles <QSO & <QSR are adjacent (share a common ray) and form a straight line with the outer rays, therefore they add up to 180.

So m<QSO+m<QSR=180.

Rewrite the equation: m<QSR=180-m<QSO

Plug the known value in: m<QSR=180-(3x-17)

Distribution & Combining like terms: m<QSR=180-3x+17=197-3x

Now solve for the 3 interior angles to equal 180.

(197-3x)+(25)+(2x+3)=180

Combine like terms: 225-x=180

Isolate the x term (-225 to both sides): -x=180-225=-45

Isolate the x (×-1 to both sides):

x=45

6 0
3 years ago
Determine the period
Tamiku [17]

assuming each grid is 1

period = 11 - 1

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2 years ago
(1 point)
inn [45]
22 ft below sea level
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Read 2 more answers
We define a bow-tie quadrilateral as a quadrilateral where two sides cross each other. An example of a bow-tie quadrilateral is
aleksandrvk [35]

Answer:

70/5985

Step-by-step explanation:

We know that a quadrilateral needs to have four vertices (or points on the circle). There are always two ways to link the cross — horizontally or vertically. Using my limited knowledge of combinations, we know that choosing four points out of seven equals 35. Multiplying the two ways to connect those lines (again, horizontally and vertically) makes 35*2 = 70 "bow-tie quadrilaterals" that can be formed on the circle using four points. There are 5985 ways four chords can be chosen out of twenty-five chords because C(25,4) equals 5985, so the probability is 70/5985... and then we just need to simplify that fraction.

3 0
3 years ago
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