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Andreas93 [3]
3 years ago
15

Given the following probabilities, determine whether

Mathematics
1 answer:
STALIN [3.7K]3 years ago
7 0

P(a) x p(b) = 2/5 x 1/4 = 2/20 = 1/10

1/10 does not equal 1/9 so the event is dependent

The answer is B ( the second choice)

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Dawn is selling her MP3 player for 3/4 of the original price. The original price for the MP3 player was $40. How much is she sel
IRISSAK [1]

Answer:

$30

Step-by-step explanation:

Have a Nice Day! :D

3 0
3 years ago
Read 2 more answers
What is 1/8 divided by 2
slavikrds [6]
When dividing 1/8 by 2
we have to first take the reciprocal of 2 
reciprocal is when the numerator and denominator are exchanged
2 when written as a fraction is \frac{2}{1}
we need to find the reciprocal of \frac{2}{1} which is \frac{1}{2}
then 
\frac{1}{2} of \frac{1}{8}
when 'of' function is used it means to multiply the 2 fractions 
when multiplying fractions multiply the numerators by numerators and multiply denominators by denominators 
is \frac{1}{2} * \frac{1}{8} =  \frac{1}{16}
answer is \frac{1}{16}

4 0
4 years ago
Read 2 more answers
How do i graph y=1/2Sinø/2?
podryga [215]
\fb \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}
\\\\
f(x)=&{{  A}}cos({{  B}}x+{{  C}})+{{  D}}\\\\
f(x)=&{{  A}}tan({{  B}}x+{{  C}})+{{  D}}
\end{array}
\\\\
-------------------

\bf \bullet \textit{ stretches or shrinks}\\
\left. \qquad   \right. \textit{horizontally by amplitude } |{{  A}}|\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\
\left. \qquad   \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\
\left. \qquad   \right. \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}

\bf \bullet \textit{function period or frequency}\\
\left. \qquad  \right. \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\left. \qquad  \right. \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)

now, with that template in mind,

\bf \stackrel{parent~function}{y=sin(\theta )}\qquad \qquad y=\stackrel{A}{\frac{1}{2}}sin\left(\stackrel{B}{\frac{1}{2}}\theta   \right)
\\\\\\
Amplitude\implies \frac{1}{2}
\\\\\\
Period\implies \cfrac{2\pi }{B}\implies \cfrac{2\pi }{\frac{1}{2}}\implies 4\pi

which is pretty much the same sin(θ) function, but squished by 1/2 and elongated up to 4π, check the picture below.


7 0
3 years ago
Which figure has the correct lines of symmetry drawn in?
RoseWind [281]
Its actually the first one because its a hexagon and that line Is the only line that can cut the shape in half
4 0
4 years ago
Read 2 more answers
I need help pls anyone​
bezimeni [28]

Answer:

5\geq m - put a closed dot on 5, then an arrow pointing to the left

Step-by-step explanation:

You have to solve the equation. After solving, you should end up with 5\geq m

5 0
3 years ago
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