B.) (1,1) (2,5) should be your answer.
Answer:
d. The width of Elly's interval will be less than the width of Drew's interval.
Step-by-step explanation:
The confidence level and the width of the confidence interval are direct proportional. This means that a confidence interval with a higher confidence level has a higher width.
For example, a 99 percent confidence interval is wider than a 90 percent confidence interval.
The midpoint of the confidence interval is the mean of the population, no matter the confidence level.
In this problem, we have that:
Elly: 90 percent CI
Drew: 99 percent CI
The correct answer is:
d. The width of Elly's interval will be less than the width of Drew's interval.
Hello!
When you put money into the bank you make a deposit
The answer is deposit
Hope this helps!
Answer:
- number of multiplies is n!
- n=10, 3.6 ms
- n=15, 21.8 min
- n=20, 77.09 yr
- n=25, 4.9×10^8 yr
Step-by-step explanation:
Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...
mpy[n] = n·mp[n-1]
mpy[2] = 2
So, ...
mpy[n] = n! . . . n ≥ 2
__
If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...
10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10
Then the larger matrices take ...
n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min
n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years
n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years
_____
For the shorter time periods (less than 100 years), we use 365.25 days per year.
For the longer time periods (more than 400 years), we use 365.2425 days per year.