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Margarita [4]
3 years ago
14

How do you use an equation to model and solve a real-world problem?

Mathematics
1 answer:
Xelga [282]3 years ago
7 0
Here's an example sally went to the store and got 13 apples when she got home her family ate 3 of the apples sally decides to go back to the store and get 5 more apples and when she returns home 3 more apples are gonna how many apples does sally have? the equation would be 13-3+5-3=12 so she has 12 apples and this represents the real world
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Which pair of points has a positive slope?
viva [34]
B.)  (1,1) (2,5) should be your answer.
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3 years ago
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Elly and Drew work together to collect data to estimate the percentage of their classmates who own a particular brand of shoe. U
ladessa [460]

Answer:

d. The width of Elly's interval will be less than the width of Drew's interval.

Step-by-step explanation:

The confidence level and the width of the confidence interval are direct proportional. This means that a confidence interval with a higher confidence level has a higher width.

For example, a 99 percent confidence interval is wider than a 90 percent confidence interval.

The midpoint of the confidence interval is the mean of the population, no matter the confidence level.

In this problem, we have that:

Elly: 90 percent CI

Drew: 99 percent CI

The correct answer is:

d. The width of Elly's interval will be less than the width of Drew's interval.

4 0
4 years ago
I do not get this question
postnew [5]
Hello!

When you put money into the bank you make a deposit

The answer is deposit

Hope this helps!
5 0
3 years ago
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Since the expression (x-4)^2+(y+1)^2 evaluated at (3,6) is
stiks02 [169]

\bf (x-4)^2+(y+1)^2\qquad (3,6)~~ \begin{cases} x = 3\\ y = 6 \end{cases}\implies (3-4)^2+(6+1)^2 \\\\\\ (-1)^2+7^2\implies 1+49\implies 50

5 0
3 years ago
Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications,
posledela

Answer:

  • number of multiplies is n!
  • n=10, 3.6 ms
  • n=15, 21.8 min
  • n=20, 77.09 yr
  • n=25, 4.9×10^8 yr

Step-by-step explanation:

Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...

  mpy[n] = n·mp[n-1]

  mpy[2] = 2

So, ...

  mpy[n] = n! . . . n ≥ 2

__

If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...

  10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10

Then the larger matrices take ...

  n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min

  n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years

  n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years

_____

For the shorter time periods (less than 100 years), we use 365.25 days per year.

For the longer time periods (more than 400 years), we use 365.2425 days per year.

8 0
3 years ago
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