Answer:
This drawn graph is the answer
Step-by-step explanation:

has CDF

where

is the CDF of

. Since

are iid. with the standard uniform distribution, we have

and so

Differentiate the CDF with respect to

to obtain the PDF:

i.e.

has a Beta distribution

.
Since each leg of the large trapezoid is bisected, then HJ is the average of the lengths of KL and NM.
HJ = (KL + NM)/2
2(HJ) = KL + nm
2(5x + 2) = 4x + 1 + 27
10x + 4 = 4x + 28
6x = 24
x = 4
KL = 4x + 1 = 4(4) + 1 = 16 + 1 = 17
Answer: KL = 17
Answer:
Step-by-step explanation:
a. 4x+4y
b. 8a+24b
c. 6x+33y
d. 63a+54b
e. 3ac+bc
f. 2xy+11yz