the answer is 16
8^(4/3) can be written in different ways. You can first simplify it by breaking the exponents down into 1/3 and 4. You can write it as (8^1/3)^4 (it still means the same thing). When you raise something to the one over something fraction, the denominator tells you what the root is. Because it says 1/3, it means that you're finding the cube root of something. So you can rewrite it as (3√8)^4 (the three should be sitting on top of the sign to signify that it's cube root). You then just solve from there. The cube root of 8 is 2 (2*2*2=8) so it'll simplify to (2)^4. You then solve it from there and get 16 as your answer (2*2*2*2=16).
Answer:
<u><em>67</em></u>
Step-by-step explanation:
<u><em>50-40+87-30</em></u>
=50+(- 40)+87(-30)
=50+87+(-40)+(-30)
=(50+87+(-40)+(-30)
=137+(-70)
=67
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<u><em>when he wins, we add points. When he loses ,we subtract points.The score is 50 points. We right an expression to find the final score </em></u>
Answer:
x = 7
Step-by-step explanation:
Rule: an even number of - signs written one after another produces a plus number.
So - - 3 = 3
The rule also lets you do something strange like
- - - - 4 = 4 but you hardly ever see this.
Rule: an odd number of minus signs produces a minus number.
x + 3 = 10 Subtract 3 from both sides.
x + 3 - 3 = 10 - 3
x = 7
Answer:

Step-by-step explanation:
The total amount of shrimp that was eaten was 12 pieces of shrimp.
To make the fraction you will simply put the amount of shrimp Jeremy ate over the total number of shrimp eaten by the pair.
Therefore, the fraction would look like this:

The decimal form of this would be 0.4167. Which also means that Jeremy ate 41.67% of the total amount of shrimp eaten.
Hope this helps!!
Answer:
4 times
Step-by-step explanation:
1 quart is equivalent to 32 fluid ounces.
If each eruption consumes 8 fluid ounces of vinegar. Assuming that the amount of vinegar required per eruption is constant, the number of times Tanvi can make her volcano erupt is:

Tanvi can make her volcano erupt 4 times with 1 quart of vinegar.