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Molodets [167]
3 years ago
7

BLOOD TYPES For every 10 people that donated blood, 3 had blood type A positive. If 51 people who had type A positive donated bl

ood, how many people donated blood?
Mathematics
1 answer:
anzhelika [568]3 years ago
6 0

Answer:add all the numbers together then divide the answer by 10

Step-by-step explanation:

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(Only for one person only and that is the fan girl)<br><br> What is 4+7-4*4/7=
pochemuha
8.71428571429 is the answer
5 0
3 years ago
The area of the right triangle shown is 24 square feet.
Stolb23 [73]

Given : A  = 24 sq feet

A = 0.5 base x height

base = x , height = x+2

A = 0.5 x(x+2)  = 24 sq feet

1) 0.5 x(x+2) = 24 (A)

2) x^2 + 2x - 48 = 0 (D)

To check the rest un-wrap the bracket:

x^2 + (x+2)^2 = 24

x^2 + x^2 + 4 + 4x = 24

2x^2 + 4x - 20 = 0

x^2 + 2x - 10= 0 (NO)

Likewise:

x^2 + (x+2)^2 = 100

x^2 + x^2  +4 + 4x = 100

2x^2 + 4x + 4 = 100

2x^2 + 4x - 96 = 0

3) x^2 + 2x - 48 = 0 (F)

To sum up: that's what apply:

1) 0.5 x(x+2) = 24 (A)

2) x^2 + 2x - 48 = 0 (D)

3) x^2 + 2x - 48 = 0 (F)

6 0
3 years ago
Read 2 more answers
If f(x)=x/2-3and g(x)=4x^2+x-4, find (f+g)(x)
Sergeeva-Olga [200]

Step-by-step explanation:

(f+g)(x) = f(x) + g(x)

= x/2-3 + 4x²+x+4

= ..........

4 0
3 years ago
Three six-sided fair dice are rolled. The six sides of each die are numbered 1; 2; : : : ; 6. Let A be the event that the first
valkas [14]

Answer:

1.) [A, B, C]

2.) [A', B', C']

3.) [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

4.) A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

Step-by-step explanation:

If A is the event that the first die shows an even number, then A' is the event that first die DOES NOT show an even number.

If B is the event that the Second die shows and even number, then B' is the event that second die DOES NOT show an even number.

If C is the event that the third die shows an even number, then C' is the event that third die DOES NOT show an even number.

Hence, our possible events are A, A', B, B', C, C'.

For question 1, in the event that all three dice show and even number, the expression of the event = [A, B, C]

For question two, in the event that no die shows an even number, the expression of the event = [A', B', C']

For question 3,In the event that at least one die shows an odd number, the expression of the event = [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

For question 4,in the event that at most two dice show odd numbers, the expression of the event = [A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

6 0
3 years ago
Plz I need some help with 11-12 . My teacher didn’t even explain it correctly so now I’m confused.
rusak2 [61]

Answer:

Step 1: Transpose everything to one side

12. x²+16x+15-10x+4=0

Step 2: Add the like terms

x² + (16x - 10x) + 15 + 4=0

x² + 6x + 19=0

Step 3: Use the quadratic formula to get the value(s) of x.

a=1 b=6 c=19

x =  \frac{ - b +  -  \sqrt{b {}^{2} - 4ac }  {}^{} }{2a}

therefore, x=... or x

6 0
3 years ago
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