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olga2289 [7]
3 years ago
12

How do i do this problem its in the test

Mathematics
1 answer:
kondaur [170]3 years ago
3 0

Answer:

First start by making an X-Y chart

I would recomend using the numbers 0, 1, and 2 as your x values for the first equation.

I would recommend -1, 1, and 2 as your x values for the second one.

Once you have your x values for each equation, plug those numbers into the equations separately. That will give you your Y values. Then all you need to do is plot your points.

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A line from the top of a cliff to the ground passes just over the top of a pole 6.0 ft. high and meets the ground at a point 7.0
Anit [1.1K]
This will solved using the concept of proportionality:
(height of the cliff)/(height of the pole)=(base of the cliff)/(length from base of pole to the rope)
thus, let the height of the cliff be x, plugging the values in the formula we obtain:
x/6=86/7
hence solving for x we get
x=(86×6)/7
x=73.71 ft
7 0
3 years ago
What is the slope - intercept form equation of the line graphed below ?
Jlenok [28]
Slope = (7-2)/(3-0) = 5/3

slope intercept b = 2

equation y= 5/3x +b

<span>answer: B. y=5/3x + 2 </span>
7 0
3 years ago
Please help!
postnew [5]
Lets solve the equation first:
<span> 0.5 – |x – 12| = –0.25
</span>= 1/2 - |x - 12| = -1/4
= 2 - 4<span>|x - 12| = -1
= 4|x - 12| = 3
= |x - 12| = 0.75
positive case, x >= 12
x - 12 = 0.75
x = 12.75
negative case, x < 12
x - 12 = -0.75
x = 11.25
So those are the two solutions.
These apply:
</span>1.) The equation will have no solutions.
2.) A good first step for solving the equation is to subtract 0.5 from both sides of the equation.
<span>3.) A good first step for solving the equation is to split it into a positive case and a negative case.
</span><span>5.) The negative case of this equation is x – 12 = –0.75.</span>
7 0
4 years ago
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They will each get 1/6 of the pizza.
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2x+20=58 then your would subtract 20 from 58 which would turn into 38 and your would divide 38/2 it would be 19 so the answer is x=19 if I’m not mistaken this is correct hope this helps
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