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Andrews [41]
2 years ago
10

25(x+5\4)^2-16(x7\4)^2 factorize the expression​

Mathematics
1 answer:
elena-s [515]2 years ago
4 0

Since both terms are perfect squares, factor using the difference of squares formula,

a² − b² = (a + b) (a − b) where a = 5(x + 5/4) and b = 4 (x (7/4) ).

− (12x + 25/4) (2x + −25/4)

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Calculate the constant of variation if y varies directly as x.
timama [110]
You have not provided the complete question (value of y at a certain value of x), therefore, I cannot give u a specific final answer. However, I can explain how to solve this problem and you can apply on the numbers you have.

y varies directly with x means that as x increases, y also increases and vice versa.
This can be represented by the following equation:
y = kx
where k is the constant of proportionality.

Solving this for k, we would find that:
k = y/x

Examples:
If we are given that y = 4 at x = 2, then:
k = y/x = 4/2 = 2
If we are given that y = 1 at x = 3, then:
k = y/x = 1/3
In general, if we are given that y = a at x = b, then:
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Hope this helps :)
6 0
3 years ago
50 x 1000<br> pls reply guys
Firdavs [7]

Answer:

50,000   fifty-thousand

Step-by-step explanation:

Just use a calculator

4 0
1 year ago
Which if the following can be contained in a plane?
andrezito [222]

Answer:

A and B im pretty sure



4 0
3 years ago
Read 2 more answers
What expression can be used to determine the cost of the buying and pounds of almonds $4.95 per pound and a half pounds of flour
Varvara68 [4.7K]

I think it is C: 4.95m + 0.72f  although this isn't in my curriculum I think its correct.

3 0
2 years ago
If y is proportional to the sqaure root of x and y equal x when x equal 5,evaluate y when x eqaul 9.​
Law Incorporation [45]

Answer:

y = 3\, \sqrt{5} when x = 9.

Step-by-step explanation:

The question states that y is proportional to \sqrt{x}. In other words, there is a constant a (a \ne 0) such that y = a\, \sqrt{x} for all x \ge 0.

The question also states that y = x when x = 5. Make use of this equality to find the value of a.

Since x = 5 and y = x, it must be true that y = 5. Substitute x = 5\! and y = 5\! into the equation y = a\, \sqrt{x} and solve for a:

5 = a\, \sqrt{5}.

\begin{aligned}a &= \frac{5}{\sqrt{5}} \\ &= \sqrt{5}\end{aligned}.

Thus, y = \sqrt{5}\, (\sqrt{x}) for all x \ge 0.

Substitute in the value x = 9 to find the corresponding value of y:

\begin{aligned} y &= \sqrt{5} \, (\sqrt{9}) \\ &= \sqrt{5} \times 3 \\ &= 3\, \sqrt{5}\end{aligned}.

6 0
2 years ago
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