Find the minimum, first quartile, median, third quartile, and maximum of each data set, 12, 10, 11, 7, 9, 10, 5
Sliva [168]
To find the median:
Least to greatest order:
5, 7, 9, 10, 10, 11, 12
10 is the number in the middle. Therefore the median is 10
Answer:
82.555
Step-by-step explanation:
Based on the given conditions, formulate:
85.23 - 2.675
Calculate the sum or difference: 82.555
12:45Answer:
Part A: 9 hours 45 minutes
Part B: $126.1575
Step-by-step explanation:
Part A,
From 7:45 to 12:15 is 4 hours and 30 minutes
From 12:45 which he clocked back in to 6:00 is 5 hours and 15 minutes.
4 hours and 30 minutes plus 5 hours and 15 minutes = 9 hours and 45 minutes.
Part B, 9 hours and 45 minutes can be represented as 9.45
And since he gets 15.35 "per" hour shows we can multiply.
15.35 x 9.45 = 126.1575
Therefor he earned 126.15.
Let point (x, y) be any point on the graph, than the distance between (x, y) and the focus (3, 6) is sqrt((x - 3)^2 + (y - 6)^2) and the distance between (x, y) and the directrix, y = 4 is |y - 4|
Thus sqrt((x - 3)^2 + (y - 6)^2) = |y - 4|
(x - 3)^2 + (y - 6)^2 = (y - 4)^2
x^2 - 6x + 9 + y^2 - 12y + 36 = y^2 - 8y + 16
x^2 - 6x + 29 = -8y + 12y = 4y
(x - 3)^2 + 20 = 4y
y = 1/4(x - 3)^2 + 5
Required answer is f(x) = one fourth (x - 3)^2 + 5
Answer:
Total area of the two rooms = (width1length1) + (width2length2)
Step-by-step explanation:
The area of the rectangular shape is given by = Length * breadth
Therefore the area of the two rooms can be calculated using the above formula when the variables lengths and widths are given.
Area 1= Area of the first room = length * breadth= (width1length1)
Area 2=Area of the second room = length * breadth= (width2length2)
Total area of the two rooms = Area1 + Area 2
= (width1length1) + (width2length2)
