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andrezito [222]
2 years ago
5

In ΔXYZ, the measure of ∠Z=90°, YX = 37, ZY = 12, and XZ = 35. What ratio represents the sine of ∠X?

Mathematics
1 answer:
m_a_m_a [10]2 years ago
7 0

Answer:

Step-by-step explanation:

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Please answer seriously thanks !! will give brainliest
deff fn [24]

Answer:

Step-by-step explanation:

21) CD -  chord   (segment)

22)FG - line

23) EC  - segment -  diameter

24) AB - segment - radius

25) H - Point

26) A - Point

4 0
2 years ago
The coordinates of ∆ABC are A(-3, 2), B(5, 8) & C(11, 0). Which type of triangle is ∆ABC? Select All that apply.
stepan [7]

Given:

The coordinates of ∆ABC are A(-3, 2), B(5, 8) & C(11, 0).

To find:

The type of the given triangle.

Solution:

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the distance formula, we get

AB=\sqrt{(5-(-3))^2+(8-2)^2}

AB=\sqrt{(8)^2+(6)^2}

AB=\sqrt{64+36}

AB=\sqrt{100}

AB=10

Similarly,

BC=\sqrt{(11-5)^2+(0-8)^2}

BC=\sqrt{(6)^2+(8)^2}

BC=\sqrt{36+64}

BC=\sqrt{100}

BC=10

And,

AC=\sqrt{(11-(-3))^2+(0-2)^2}

AC=\sqrt{(14)^2+(-2)^2}

AC=\sqrt{196+4}

AC=\sqrt{200}

AC=10\sqrt{2}

Two sides of the triangle are equal, i.e., AB=BC. So, the triangle is an isosceles triangle.

Sum of square of two smaller side is

AB^2+BC^2=10^2+10^2

AB^2+BC^2=100+100

AB^2+BC^2=200

AB^2+BC^2=AC^2

Using the Pythagoras theorem, we can say that the given triangle is a right triangle.

Therefore, the correct options are B and F.

7 0
3 years ago
Helpppp
Vanyuwa [196]

Answer:

?

Step-by-step explanation:

7 0
3 years ago
Suppose that an object moves along the y-axis so that its location is y=x2+3x at time x. (Here y is in meters and x is in second
vfiekz [6]

Answer:

a) 13 m/s

b) (15  + h) m/s

c) 15 m/s

Step-by-step explanation:

if the location is

y=x²+3*x

then the average velocity from 3 to 7 is

Δy/Δx=[y(7)-y(3)]/(7-3)=[7²+3*7- (3²+3*3)]/4= 13 m/s

then the average velocity from x=6 to to x=6+h

Δy/Δx=[y(6+h)-y(6)]/(6+h-6)=[(6+h)²+3*(6+h)- (6²+3*6)]/h= (2*6*h+3*h+h²)/h=2*6+3= (15 + h) m/s

the instantaneous velocity can be found taking the limit of Δy/Δx when h→0. Then

when h→0 , limit Δy/Δx= (15 + h) m/s = 15 m/s

then v= 15 m/s

also can be found taking the derivative of y in x=6

v=dy/dx=2*x+3

for x=6

v=dy/dx=2*6+3 = 12+3=15 m/s

7 0
2 years ago
How to find the perimeter ratio of two similar triangles
Free_Kalibri [48]

Answer:

of their perimeters is equal to the ratio of their corresponding side lengths. ratio of their areas is equal to the square of the ratio of their corresponding side lengths.

5 0
3 years ago
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