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LekaFEV [45]
2 years ago
12

what is 23456776543211234654345676543456765434567654.5096875849 divided by 234.5678765424587654357876543 divided by 9999?

Mathematics
2 answers:
galina1969 [7]2 years ago
7 0

Answer: Haha i'm so sorry but i don't know.

Step-by-step explanation: Have a great day!

kow [346]2 years ago
6 0

Answer:

1.0000995e+37

Step-by-step explanation:

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Gradient of line AB (3,7) and (5,11)​
larisa [96]

Answer:

Gradient is change in y over change in x.

gradient = y1-y2 ÷ x1-x2

=7-11 ÷ 3-5

=-4 ÷ -2

=2

4 0
3 years ago
Read 2 more answers
Need help for 18) 21) Solve each equation and check. Show all work please
Alexxandr [17]
18) (10)7d/10=35(10)
7d/7=350/7
d=50
21) 3/4 w=27
(4/3)3/4 w=27(4/3)
w=36
Hope this helps!
5 0
3 years ago
Which is the image of -2,5 reflected across x=2?
Basile [38]

Answer:

6,5

Step-by-step explanation:

-2 is 4 down from 2, so reflected should be 4 up, or 6

3 0
3 years ago
Find the area of the triangle below.
Phoenix [80]

Answer:

20.25

Step-by-step explanation:

Just multiply the base and height then divide the results in half.

Hope this helps!

5 0
2 years ago
Which is the distance between parallel lines with the equations 3x-5y=1 and 3x-5y=-3
jonny [76]

Answer:

The distance between parallel lines is 0.6860\ units

Step-by-step explanation:

we have

3x-5y=1 -----> equation A

3x-5y=-3 -----> equation B

Line A and Line B are parallel lines, because their slopes are equal

Step 1

Find the slope of the given lines

isolate the variable y in the equation A

5y=3x-1

y=(3/5)x-1/5

The slope is m=(3/5)

Step 2

Find the slope of the perpendicular line to the given lines

we know that

If two lines are perpendicular, then the product of their slopes is equal to -1

so

m1*m2=-1

we have

m1=3/5 -----> given lines

substitute

(3/5)*m2=-1

m2=-5/3

Step 3

Find the equation of the perpendicular line that pass though the origin

 with the slope  m2=-5/3 and the point (0,0) Find the equation of the line

y-y1=m(x-x1)

y-0=(-5/3)(x-0)

y=-(5/3)x

Step 4

Using a graphing tool

Graph the two parallel lines and the perpendicular line

The intersection points are

A(-0.2647,0.4412) and B(0.0882,-0.1471)  

see the attached figure

we know that

the distance between the points A and B is the distance between parallel lines

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

substitute the values

d=\sqrt{(-0.1471-0.4412)^{2}+(0.0882+0.2647)^{2}}

d=\sqrt{(-0.5883)^{2}+(0.3529)^{2}}

d=0.6860\ units

8 0
3 years ago
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