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anzhelika [568]
3 years ago
8

Helpppp ahhhhhhh plz

Mathematics
1 answer:
kaheart [24]3 years ago
3 0

Answer:

It's Parallel

Step-by-step explanation:

Perpendicular have to intersect  

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Over the last four years, the common stock of Plymouth Shippers has had an arithmetic average return of 10.4 percent. Three of t
brilliants [131]

Answer:

57.9

Step-by-step explanation:

8 0
3 years ago
The slope is undefined and contains the point (-3,8)
Yakvenalex [24]
Undefined slope = straight vertical line
Which would be an equation like x =...
for this point it is x = -3
8 0
3 years ago
Find the average rate of change of the function f(x) = 1/x-2 between the given points x = 4 and x = 8​
Sedbober [7]

If <em>f(x)</em> = 1/<em>x</em> - 2, then the average rate of change between <em>x</em> = 4 and <em>x</em> = 8 is

(<em>f</em> (8) - <em>f</em> (4)) / (8 - 4) = ((1/8 - 2) - (1/4 - 2)) / 4 = -1/16

If you meant <em>f(x)</em> = 1/(<em>x</em> - 2), then it would be

(<em>f</em> (8) - <em>f</em> (4)) / (8 - 4) = (1/(8 - 2) - 1/(4 - 2)) / 4 = (1/6 - 1/2) / 4 = -1/12

<em>Make sure to check which one is the correct function!</em>

7 0
2 years ago
You are playing a board game with your little sister. Moves are determined by rolling 2 six-sided dice. The red die tells you th
enot [183]

Answer: The probability is 1/9.

Step-by-step explanation:

First, let's define the possible outcomes of each dice:

Red: Forward (4 times), Backward (2 times)

Green : {1, 1, 2, 2, 3, 4}

We want to find the probability of moving backward 2 spaces.

Then we need to find the probability of rolling a "backward" in the red dice, and a 2 in the green dice.

First, the probability of rolling a backward in the red dice is equal to the quotient between the number of outcomes that are "backward", and the total number of outcomes in the dice (there are 2 backwards and 6 outcomes in total), this is:

p1 = 2/6 = 1/3.

And the probability of rolling a 2 in the green dice is equal to the quotient between the number of outcomes with a 2, and the total number of outcomes. (The 2 appears two times, and there are 6 possible outcomes):

p2 = 2/6 = 1/3.

Now, the probability of both events happening at the same time is equal to the product of the individual probabilities, then the probability of moving backwards 2 spaces is:

P = p1*p2 = (1/3)*(1/3) = 1/9.

7 0
3 years ago
5.Solve the system using substitution.
Nikolay [14]
OK first convert one of the equations into Y=MX+b form

Y-2x = 3
Add 2X

Y = 2x +3
Now substitute this equation in the other one.
So it would be

3X - 2Y = 5

3X-2(2x+3) = 5

Now solve for y

3X - 4X - 6 = 5

-1X - 6 = 5

Add 6

-1X = 11

X = -11

Now substitute this into one of the equations

Y - 2X = 3

Y -2(-11) = 3

Y +22 = 3

y = 3-22

y = -19


8 0
3 years ago
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