Answer:

Step-by-step explanation:

<, > - open circle
≤, ≥ - closed circle
<, ≤ - draw the line to the left
>, ≥ - draw the line to the right
Answer:
0.51 cm
Step-by-step explanation:
In right triangle MNP, MP = 4 cm, m∠N = 90°, m∠P = 21°
By the sine definition,

Now, consider right triangle HMN (it is right because NH is an altitude). By the cosine definition,

In the right triangle, two acute angles are always complementary, so

Thus,

2.5 weighs more. It’s a greater number than 2.48
Answer:
91
Step-by-step explanation:
273 divded by 3
Answer:
There are 2
(6 2/5, -6 2/5)
(8 3/5, 4 2/5)
Step-by-step explanation: