Let the integers be x-1, x, x+1.
Given,
x -1 + x + x + 1 = 21 + 2(x - 1)
3x = 21 + 2x - 2
x = 19
Hence, the three integers are 18, 19 and 20.
Answer:
sqrt(A/pi), -sqrt(A/pi)
Step-by-step explanation:
A=pi*r^2
r^2=A/pi
r=sqrt(A/pi), -sqrt(A/pi)
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Answer:
if the equation if f(x) = 3x + 2, then f(5) would be equal to 3*5 + 2 = 17.
Step-by-step explanation:
Answer:
Step-by-step explanation:
G(f(2+x))=g(2+x)^2+3(2+x)=2(2+x)^2+3(2+x)-2=2(4+4x+x^2)+6+3x=8+8x+2x^2+6+3x=2x^2+11x+14
