All categories

3 years ago

The width of a rectangular room is 60% of its length. The length of the room is 10 feet. What is the area of the room?

Mathematics

2 answers:

Dafna1 [17]3 years ago

8 0

The answer is 60 square feet.

Schach [20]3 years ago

5 0

Answer:

60 square feet

Step-by-step explanation:

10% of 10 is 1 so 60% of 10 would be 6. 6 x 10 = 60

You might be interested in

Regina's mom bought her some bracelets. There were a total of 85 bracelets in 5 packages.

adelina 88 [10]

The answer your looking for is B

8 0

3 years ago

What is -3x-5 = 16 I'm stuck on a simple problem

mariarad [96]

Answer:

-7

Step-by-step explanation:

-3x-5=16

-3x-5+5=16+5

-3x=21

-3x/-3=21/-3

x=-7

4 0

3 years ago

Read 2 more answers

Three planes intersect in Select one: O a. a plane O b. a point O c. a line segment

Arada [10]

Answer:

a line segment ✓....,.........

5 0

3 years ago

Rico walked for 3/10 mile. Then he walked for 24/100 mile. How far did he walk in all?

grigory [225]

First, Rico walked for 3/10 of a mile which is 30/100 of a mile.
Hen, Rico walked for 24/100 of a mile.
Then you add 24/100 and 30/100. 24+30/100 which is 54/100.
Answer=54/100 of a mile

4 0

4 years ago

Read 2 more answers

A particle is moving along the x-axis so that its position at t ≥ 0 is given by s(t)=(t)ln(5t). Find the acceleration of the par

lyudmila [28]

Answer:

$a(\frac{1}{5e})=5e$

Step-by-step explanation:

we are given equation for position function as

$s(t)=tln(5t)$

Since, we have to find acceleration

For finding acceleration , we will find second derivative

$s'(t)=\frac{d}{dt}\left(t\ln \left(5t\right)\right)$

$=\frac{d}{dt}\left(t\right)\ln \left(5t\right)+\frac{d}{dt}\left(\ln \left(5t\right)\right)t$

$=1\cdot \ln \left(5t\right)+\frac{1}{t}t$

$s'(t)=\ln \left(5t\right)+1$

now, we can find derivative again

$s''(t)=\frac{d}{dt}\left(\ln \left(5t\right)+1\right)$

$=\frac{d}{dt}\left(\ln \left(5t\right)\right)+\frac{d}{dt}\left(1\right)$

$=\frac{1}{t}+0$

$a(t)=\frac{1}{t}$

Firstly, we will set velocity =0

and then we can solve for t

$v(t)=s'(t)=\ln \left(5t\right)+1=0$

we get

$t=\frac{1}{5e}$

now, we can plug that into acceleration

and we get

$a(\frac{1}{5e})=\frac{1}{\frac{1}{5e}}$

$a(\frac{1}{5e})=5e$

5 0

3 years ago