I need help please with this math problem.
1 answer:
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Answer:
The 98% of the confidence interval for the true average salary of Knirhsdaeh employees as a psychology counselor
(75.4206, 86.5794)
Step-by-step explanation:
<u><em>Step(i):-</em></u>
<em>Given that the mean of the sample = $81 k</em>
<em>Given that the size of the sample 'n' = 23</em>
<em>Given that the standard deviation for the salaries is $13 k</em>
<u><em>Step(ii):-</em></u>
<u><em>98% of the confidence interval for the true average salary of Knirhsdaeh employees is determined by</em></u>
<u><em /></u><u><em /></u>
<u><em>Degrees of freedom = n-1 = 23-1 =22</em></u>
<u><em /></u><u><em /></u>
( 81 - 5.57940 , 81 + 5.57940)
(75.4206, 86.5794)
<u><em>Final answer:-</em></u>
The 98% of the confidence interval for the true average salary of Knirhsdaeh employees as a psychology counselor
(75.4206, 86.5794)