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Marrrta [24]
3 years ago
12

What is r? r = one-third r = 3 r = two-thirds r = one-half

Mathematics
2 answers:
Softa [21]3 years ago
8 0

Answer:

what is the equation.

Step-by-step explanation:

comment the equation

Brilliant_brown [7]3 years ago
3 0

Answer:

r = r

 -incomplete

Step-by-step explanation:

since there is no equation or no limitations along with the question, i cannot say what r can be, if there is an equation or additional info I can better tell you, but rn, r literally is equal to all of those answers

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Look at the picture.

Therefore we have the equation:

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y = 16



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7 0
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Prove the trigonometric identity
Annette [7]

Answer:

Proved See below

Step-by-step explanation:

Man this one is a world of its own :D Just a quick question are you a fellow Add Math student in O levels i remember this question from back in the day :D Anyhow Lets get started

For this question we need to know the following identities:

1+tan^{2}x=sec^2x\\\\1+cot^2x=cosec^2x\\\\sin^2x+cos^2x=1

Lets solve the bottom most part first:

1-\frac{1}{1-sec^2x} \\\\

Take LCM

1-\frac{1}{1-sec^2x} \\\\\frac{1-sec^2x-1}{1-sec^2x} \\\\\frac{-sec^2x}{1-sec^2x} \\\\\frac{-(1+tan^2x)}{-tan^2x}

now break the LCM

\frac{-1}{-tan^2x}+\frac{-tan^2x}{-tan^2x}\\\\\frac{1}{tan^2x}+1\\\\cot^2x+1

because 1/tan = cot x

and furthermore,

cot^2x+1\\cosec^2x

now we solve the above part and replace the bottom most part that we solved with cosec^2x

\frac{1}{1-\frac{1}{cosec^2x} } \\\\\frac{1}{1-sin^2x} \\\\\frac{1}{cos^2x}\\\\sec^2x

Hence proved! :D

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denis-greek [22]
My answer is isn't on the choices and I can't show you how I got it. My answer is in the attached files.

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