Answer:
Step-by-step explanation:
Product of slope of perpendicular lines = -1
6x + 5y = 30
Write this equation in y = mx + b form
5y = -6x + 30
y = 

Slope of this line m₁ = -6/5
m₁ * m₂ = -1
m₂ = -1÷m₁ = -1 *
& (-6 , -7)
Equation of the required line: y - y₁ = m (x - x₁)
![y - (-7) = \frac{5}{6}(x - [-6])\\\\y + 7 = \frac{5}{6}x + 6 *\frac{5}{6}\\\\y = \frac{5}{6}x +5-7\\\\y=\frac{5}{6}x-2](https://tex.z-dn.net/?f=y%20-%20%28-7%29%20%3D%20%5Cfrac%7B5%7D%7B6%7D%28x%20-%20%5B-6%5D%29%5C%5C%5C%5Cy%20%2B%207%20%3D%20%5Cfrac%7B5%7D%7B6%7Dx%20%2B%206%20%2A%5Cfrac%7B5%7D%7B6%7D%5C%5C%5C%5Cy%20%3D%20%5Cfrac%7B5%7D%7B6%7Dx%20%2B5-7%5C%5C%5C%5Cy%3D%5Cfrac%7B5%7D%7B6%7Dx-2)
I got the factors of 40 but both numbers do not add up to 11. Negative numbers are not considered because the product and sum are positive numbers.
1 x 40 = 40 1 + 40 = 41
2 x 20 = 40 2 + 20 = 22
4 x 10 = 40 4 + 10 = 14
5 x 8 = 40 5 + 8 = 13
I also got the addends of 11 and solved each set to get the product
1 + 10 = 11 1 x 10 = 10
2 + 9 = 11 2 x 9 = 18
3 + 8 = 11 3 x 8 = 24
4 + 7 = 11 4 x 7 = 28
5 + 6 = 11 5 x 6 = 30
(-2,5)(9,-6)
slope(m) = (-6-5) / (9 - (-2) = -11/11 = -1
y = mx + b
slope(m) = -1
(-2,5)...x = -2 and y = 5
now we sub and solve for b, the y int
5 = -1(-2) + b
5 = 2 + b
5 - 2 = b
3 = b
so ur equation in slope intercept form is : y = -x + 3