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Mashutka [201]
3 years ago
5

Help me please!!!!!!!!!!!!!

Mathematics
2 answers:
blsea [12.9K]3 years ago
8 0

Answer:

A

Step-by-step explanation:

Using the midpoint formula

[ 0.5(x₁ + x₂), 0.5(y₁ + y₂ ) ]

with (x₁, y₁ ) = (- 4, 6) and (x₂, y₂ ) = (4, - 2), then

midpoint = [ 0.5(- 4 + 4), 0.5(6 - 2) ] = [0.5(0), 0.5(4) ] = (0, 2 )  → A

marusya05 [52]3 years ago
7 0

Answer:

B.) (0,1)

Hope this helps : )

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Answer:

a) P(\bar X

b)P(98

c) P(\bar X

d) P(93

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(99.9,30)  

Where \mu=99.9 and \sigma=30

We select a random sample of n=36. And from the central limit theorem we know that the distribution for the sample is given by:

\bar X \sim N(\mu =99.9 , \frac{\sigma}{\sqrt{n}}= \frac{30}{\sqrt{38}}=4.87)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

If we apply this formula to our probability we got this:

P(\bar X

=P(Z

Part b

For this case we want this probability:

P(98

=P(\frac{98-99.9}{\frac{30}{\sqrt{38}}}

And we can find this probability on this way:

P(-0.39

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(-0.39

Part c

If we apply this formula to our probability we got this:

P(\bar X

P(\bar X

Part d

For this case we want this probability:

P(93

=P(\frac{93-99.9}{\frac{30}{\sqrt{38}}}

And we can find this probability on this way:

P(-1.42

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(-1.42

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