Answer:
a)At the 10% significance level, we fail to reject the null hypothesis.
b) P-value is ≈ 0.48
Step-by-step explanation:
Let p be the proportion of the auditors agree with the statement "Cash flow is an important indicator of profitability."
Then,
: p=0.5
: p≠0.5
Test statistic can be calculated as:
z=
where
- p(s) is the sample proportion of the auditors agree with the statement. (
=0.525)
- p is the proportion assumed under null hypothesis. (0.5)
- N is the sample size (200)
Using these numbers we get:
z=
≈0,707
and p(z) is ≈ 0.48. Since 0.48>0.10, the result is not significant at 90% level. Therefore we fail to reject the null hypothesis.
Answer:
987.76 Hz
Step-by-step explanation:
You have B4's frequency of 493.88 Hz and you want to know the frequency of the note one octave <u>above</u> B4.
When you go up an octave, you double the original frequency. When you go down an octave, you divide the original frequency by two.
So, since B4's frequency is about 493.88 Hz, an octave above would be 2 x 493.88 Hz or 987.76 Hz
If we were looking for an octave below B4, we would divide 493.88 Hz by 2 to get 246.94 Hz.
Answer:
x = -14/5
Step-by-step explanation:
Given: 8^(3x+4) = 4^(2x-1)
Rewrite with same base: (2^3)^(3x+4) = (2^2)^(2x-1)
Use exponent rules: 2^(3(3x+4)) = 2^(2(2x-1))
Eliminate bases: 3(3x+4) = 2(2x-1)
9x+12 = 4x-2
5x+12 = -2
5x = -14
x = -14/5
-3/7 + -3/4= 33/28 or 1 5/28
Answer: B. C(n)=0.75n-0.25
Hope these helped u :)
Step-by-step explanation: