Question

4. Calculate the number of carbon (C) atoms present in the 25 mL of sugar.

Answer 1

Answer: $8.38\times 10^{23}atoms$ of carbon

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

mass of sugar= $density\times volume=1.59g/ml\times 25ml=39.75g$

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{39.75g}{342.3g/mol}=0.116moles$

1 mole of sugar $C_{12}H_{22}O_{11})$ contains = $12\times 6.023\times 10^{23}=72.28\times 10^{23}atoms$ of carbon

0.116 mole of sugar $C_{12}H_{22}O_{11})$ contains = $\frac{72.28\times 10^{23}}{1}\times 0.116=8.38\times 10^{23}atoms$ of carbon