explain why samples of gold and copper can have the same extensive properties, but not the same intensive properties

1 answer:

3 0

Extensive properties, as volume and mass, depend on the amount of material. So, you can have a sample of gold and a sample of copper with the same volume as long as you have different amount of each one.

On the other hand, intensive properties do not depend on the amound of material but on the chemical constitution of the material. Density is an intensive property, so gold and copper have different densities. That is why you can use intensive properties to characterize different materials.

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What is the value of for this aqueous reaction at 298 K? A+B↽⇀C+D ΔG°=12.86 kJ/mol K=

agasfer [191]

Answer:

The equilbrium constant is 179.6

Explanation:

To solve this question we can use the equation:

ΔG = -RTlnK

Where ΔG is Gibbs free energy = 12.86kJ/mol

R is gas constant = 8.314x10⁻³kJ/molK

T is absolute temperature = 298K

And K is equilibrium constant.

Replacing:

12.86kJ/mol = -8.314x10⁻³kJ/molK*298K lnK

5.19 = lnK

e^5.19 = K

179.6 = K

<h3>The equilbrium constant is 179.6</h3>

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3 years ago

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ludmilkaskok [199]

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Hope it helps you.....

The answer is in form of image..

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3 years ago

C10H12O4S(s) + O2(g)  CO2(g) + SO2(g) + H2O(g)

ale4655 [162]

Answer: The coefficient for $O_2(g)$ is 12.

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

$C_{10}H_{12}O_4S(s)+12O_2(g)\rightarrow 10CO_2(g)+SO_2(g)+6H_2O$