Answer:
1.274 moles
Explanation:
The equation for the reaction can be represented as follows:
⇄
+ 
K = 0.060
K = ![\frac{[PCl_3][Cl_2]}{[PCl_5]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BPCl_3%5D%5BCl_2%5D%7D%7B%5BPCl_5%5D%7D)
Concentration of
= 
Concentration of
= 
Concentration of
= 0.398 moles
If we construct an ICE table for the above equation; we have:
⇄
+ 
Initial 0.398 0 0
Change - x + x + x
Equilibrium (0.398 - x) x x
K = ![\frac{[PCl_3][Cl_2]}{[PCl_5]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BPCl_3%5D%5BCl_2%5D%7D%7B%5BPCl_5%5D%7D)
K = ![\frac{[x][x]}{[0.398-x]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Bx%5D%5Bx%5D%7D%7B%5B0.398-x%5D%7D)
K = 
0.060 = 
0.06(0.398-x) = x²
0.02388 - 0.060x = x²
x² + 0.060x - 0.02388 = 0 (quadratic equation)
a = 1; b= 0.06; c= -0.02388
Using quadratic formula;
= 
= 
= 
= 
= 
=
or 
=
or 
= 0.1274 or -0.1874
We go by the positive value which says:
[x] = 0.1274 M
number of moles = 0.1274 × 10.0
= 1.274 moles
∴ the number of moles of Cl₂ produced at equilibrium = 1.274 moles
For every meter, the equivalent measurements is 1000 millimeters. Hence in the problem where the number of millimeters is given, we divide the number by 1000 to get the number of meters. The answer here is 0.01123 m.
I would assume so.
Given

, we can simplify the fraction to

Both would obtain the same proportions, so I don't see why putting a half cup of sugar would make things any different.
Hope this is the answer you are looking for.
760.0 mmHg(V)=600.0mmHg(240.0mL)
600(240)/760=189mL
Answer:
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