9.) Write the following mixed number as an improper fraction. 7 3/5

Mathematics

1 answer:

VladimirAG [237]2 years ago

7 0

7 3/5 = 7x5=35 +3 = 38/5

You might be interested in

Which quadratic function in standard form has the values a = –3.5, b = 2.7, and c = –8.2?

sweet-ann [11.9K]

Answer:

f(x)=-3.5x²+2.7x - 8.2

Step-by-step explanation:

We have given:

a = -3.5 , b=2.7 and c= -8.2

We have to write quadratic function in standard form.

We know that the standard form of quadratic function is:

f(x)=ax²+bx+c

where a, b, and c being constants, or numerical coefficients, and x is an unknown variable.

We have the values a= -3.5 , b = 2.7 and c = -8.2

Substitute the values in the standard form:

f(x)=-3.5x²+2.7x - 8.2

Therefore the answer is: f(x)=-3.5x²+2.7x - 8.2 ....

6 0

3 years ago

How many integers in the set {n ∈ Z | 1 ≤ n ≤ 700} are divisible by 2 or 7?

sukhopar [10]

$\large\begin{array}{l}\\\\ \textsf{This question gives us a set}\\\\ \mathsf{S=\{n \in\mathbb{Z}:~1\le n\le 700\}}\\\\ \mathsf{S=\{1,\,2,\,3,\,\ldots,\,699,\,700\}}\\\\\\ \bullet~~\textsf{Set of integers that are divible by 2 (even integers):}\\\\ \mathsf{A=\{n\in \mathbb{Z}:~n=2k,\,k\in\mathbb{Z}\}}\\\\ \mathsf{A=\{\ldots,\,-4,\,-2,\,0,\,2,\,4,\,\ldots\}}\\\\\\ \bullet~~\textsf{Set of integers that are divible by 7:}\\\\ \mathsf{B=\{n\in \mathbb{Z}:~n=7k,\,k\in\mathbb{Z}\}}\\\\ \mathsf{A=\{\ldots,\,-14,\,-7,\,0,\,7,\,14,\,\ldots\}} \end{array}$

___________

$\large\begin{array}{l}\\\\ \textsf{We want to know how many elements there are in the}\\\textsf{following set:}\\\\ \mathsf{S\cap (A\cup B)=(S\cap A)\cup(S\cap B)\qquad(i)} \end{array}$

____________

$\large\begin{array}{l}\\\\ \bullet~~\mathsf{S\cap A=\{n\in\mathbb{N}:~n=2k~~and~~1\le n\le 700,\,k\in\mathbb{Z}\}}\\\\ \mathsf{S\cap A=\{2,\,4,\,6,\,\ldots,\,698,\,700\}}\\\\ \mathsf{S\cap A=\{1\cdot 2,\,2\cdot 2,\,3\cdot 2,\,\ldots,\,349\cdot 2,\,350\cdot 2\}}\\\\\\ \textsf{So, there are 350 elements in }\mathsf{S\cap A:}\\\\ \mathsf{\#(S\cap A)=350.} \\\\\\ \bullet~~\mathsf{S\cap B=\{n\in\mathbb{N}:~n=7k~~and~~1\le n\le 700,\,k\in\mathbb{Z}\}}\\\\ \mathsf{S\cap B=\{7,\,14,\,21,\,\ldots,\,693,\,700\}}\\\\ \mathsf{S\cap B=\{1\cdot 7,\,2\cdot 7,\,3\cdot 7,\,\ldots,\,99\cdot 7,\,100\cdot 7\}} \\\\\\ \textsf{So, there are 100 elements in }\mathsf{S\cap B:}\\\\ \mathsf{\#(S\cap B)=100.} \end{array}$

____________

$\large\begin{array}{l}\\\\ \textsf{Therefore,}\\\\ \mathsf{\#\big[S\cap (A\cup B)\big]}\\\\ =\mathsf{\#\big[(S\cap A)\cup(S\cap B)\big]}\\\\ =\mathsf{\#(S\cap A)+\#(S\cap B)-\#\big[(S\cap A)\cap(S\cap B)\big]}\\\\ =\mathsf{350+100-50}\\\\ =\mathsf{450-50}\\\\ =\mathsf{400~elements.}\\\\\\ \textsf{There are 400 integers in S that are divisible by 2 or 7.} \end{array}$

If you're having problems understanding the answer, try to see it through your browser: brainly.com/question/2105863

$\large\begin{array}{l}\\\\ \textsf{Any doubts? Please, comment below.}\\\\\\ \textsf{Best wishes! :-)} \end{array}$

Tags: <em>set theory divibilility divisible integers union intersection</em>

3 0

3 years ago

If 2/5 of the macaroni and cheese provides 16 pieces to the table,how many pieces were in the pan when it was full? Support you

astra-53 [7]

Bearing in mind that a whole will be 5/5, so the full pan is 5/5.

$\bf \begin{array}{ccll}
macaroni&pieces\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
\frac{2}{5}&16\\\\
\frac{5}{5}&p
\end{array}\implies \cfrac{\quad\frac{2}{5} \quad }{\frac{5}{5}}=\cfrac{16}{p}\implies \cfrac{2}{5}\cdot \cfrac{5}{5}=\cfrac{16}{p}
\\\\\\
\cfrac{2}{5}=\cfrac{16}{p}\implies 2p=80\implies p=\cfrac{80}{2}\implies p=40$

8 0

3 years ago

Evaluate the expression –0.4(3x – 2) + 2x+4/3 for x=4

fomenos

Answer:

-1.07

Step-by-step explanation:

–0.4(3x – 2) + 2x+4/3

–0.4(24 – 2) + 8+4/3

-9.6-0.8+8+1.33

-2.4+1.33

-1.07