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2 years ago

I need help plzzzzz this is really confusing

Mathematics

2 answers:

meriva2 years ago

7 0

<h3>Answer: Choice B</h3>

Explanation:

The blue shaded region describes any x value that is smaller than -3, or that is equal to -3. We can phrase it as "x is less than or equal to -3". Therefore, that's why we go for $x \le -3$

If you graphed $x < -3$ , without the "or equal to" portion, then you would have an open circle at the endpoint. The open circle means we don't include that value as part of the solution set.

Anuta_ua [19.1K]2 years ago

5 0

Answer:

B. <u>x</u><u><</u><u> </u>-3

hope it helps.

<h3>stay safe healthy and happy.</h3>

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anyanavicka [17]

ANSWER

$x = 2 \: \: or \: \: x = 15$

$x = - 2 \: \: or \: \: x = - 15$

EXPLANATION

The given polynomial is

$f(x) = {x}^{2} + kx + 30$

where a=1,b=k, c=30

Let the zeroes of this polynomial be m and n.

Then the sum of roots is

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The square difference of the zeroes is given by the expression.

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From the question, this difference is 169.

This implies that:

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$k^{2} = 289$

$k= \pm \sqrt{289}$

$k= \pm17$

We substitute the values of k into the equation and solve for x.

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The zeroes are given by;

$(x \pm2)(x \pm 15) = 0$

$x = \pm2 \: \: or \: \: x = \pm 15$

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