All categories

2 years ago

PLEASE HELP QUICK !!

Mathematics

1 answer:

babunello [35]2 years ago

4 0

Step-by-step explanation:

given f(x) = 2/x and g(x) = 2/x

f(g(x)) = 2/(g(x)) = 2/2/x = x/2 × 2 = x

g(f(x)) = 2/(f(x)) = 2/2/x = x/2 × 2 = x

therefore they are inverses

since f(g(x)) = g(f(x)) = x.

You might be interested in

A train leaves a station and travels north at a speed of 105105 km/h. twotwo hours later, a second train leaves on a parallel

hram777 [196]

Let x = hours to meet

train one has a 2 hour head start or 210 km head start

210 + 105x = 135x
30x = 210
x = 7 hours to meet

6 0

3 years ago

Find the 2th term of the expansion of (a-b)^4.

vladimir1956 [14]

The second term of the expansion is $-4a^3b$ .

Solution:

Given expression:

$(a-b)^4$

To find the second term of the expansion.

$(a-b)^4$

Using Binomial theorem,

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here, a = a and b = –b

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

Substitute i = 0, we get

$$\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}=1 \cdot \frac{4 !}{0 !(4-0) !} a^{4}=a^4$

Substitute i = 1, we get

$$\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}=\frac{4 !}{3!} a^{3}(-b)=-4 a^{3} b$

Substitute i = 2, we get

$$\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}=\frac{12}{2 !} a^{2}(-b)^{2}=6 a^{2} b^{2}$

Substitute i = 3, we get

$$\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}=\frac{4}{1 !} a(-b)^{3}=-4 a b^{3}$

Substitute i = 4, we get

$$\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}=1 \cdot \frac{(-b)^{4}}{(4-4) !}=b^{4}$

Therefore,

$$(a-b)^4=\sum_{i=0}^{4}\left(\begin{array}{l}4 \\i\end{array}\right) a^{(4-i)}(-b)^{i}$

$=\frac{4 !}{0 !(4-0) !} a^{4}(-b)^{0}+\frac{4 !}{1 !(4-1) !} a^{3}(-b)^{1}+\frac{4 !}{2 !(4-2) !} a^{2}(-b)^{2}+\frac{4 !}{3 !(4-3) !} a^{1}(-b)^{3}+\frac{4 !}{4 !(4-4) !} a^{0}(-b)^{4}$ $=a^{4}-4 a^{3} b+6 a^{2} b^{2}-4 a b^{3}+b^{4}$

Hence the second term of the expansion is $-4a^3b$ .

3 0

2 years ago

Simplify 3^2 x 2^4 x 3^3 x 2

alex41 [277]

3²×2^4 ×3³×2=
3^5×2^5=
243 × 32 = 7776

3 0

3 years ago

The number name of 70080067 <br>In Indian System

zloy xaker [14]

Answer:

Seven crore eighty thousands sixty-seven.

Step-by-step explanation:

70080067

Seven crore eighty thousands sixty-seven.

3 0

2 years ago

The function table shows the rule y = 3x + 5. Which number correctly completes the table?

Oduvanchick [21]

Answer:

the answer is 3

Step-by-step explanation:

11-8=3

17-11=6

6/2=3

8 0

2 years ago

Read 2 more answers