Well the P should probably be 4
Solution-
First 9 letters of alphabet are- A,B,C,D,E,F,G,H,I
Total number of ways of selection of 4 letters from 9 alphabets = 9C4
=9!÷((4!).(9-4)!) = 9!÷(4!×5!) = (9×8×7×6)÷(24) = 126
The number of ways of arranging these 4 numbers = 4! = 24
∴ Total number of possible permutations = 9C4×4! = 126×24 = 3024
∴ option number 2 is correct.
Answer:
5x+2=0
Step-by-step explanation:
When factoring you add or subtract your factors that are similar.
For example 9x-4x+ 5x
and this is how you get 5x+2=0
Any Questions?
2/3 x 3/4 =6/12=1/2
(Multiply numerators, multiply denominators, simplify)
