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Sonja [21]
3 years ago
14

. What are the lower, middle, and upper quartiles of this data? 23, 15, 22, 15, 23, 15, 13, 21, 14 a. lower: 15, middle: 15, upp

er: 22 b.lower: 14, middle: 15, upper: 23 c.lower: 13, middle: 15, upper: 23 d.lower: 14.5, middle: 15, upper: 22.5
Mathematics
2 answers:
Serggg [28]3 years ago
5 0

Answer:

Last option: lower quartile = 14.5, middle = 15 and upper quartile = 22.5

Step-by-step explanation:

The given data is 23, 15, 22, 15, 23, 15, 13, 21, 14.

And we have to calculate lower, middle and upper quartiles of this data.

For this we arrange the numbers from lowest to highest.

13, 14, 15, 15, 15, 21, 22, 23, 23.

in this sequence the first quarter is 13, 14, 15, 15

Therefore the lower quartile will be = (14 + 15)/2 = 29/2 = 14.5

Middle term or middle is 15.

Second quarter is 21, 22, 23, 23

Therefore the upper quartile will be = average of the middle terms = (22+23)/2 = 45/2 = 22.5

Therefore lower quartile = 14.5, middle = 15 and upper quartile = 22.5

icang [17]3 years ago
4 0
The correct answer us D. lower: 14.5 middle: 15 upper: 22.5
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almond37 [142]

Answer:

The distance from the balloon to the soccer fields = 3.6 miles ⇒ answer (b)

Step-by-step explanation:

* Let the hot air balloon  at point A , the soccer fields

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∵ The measure of the angle of depression to the

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* The distance between the balloon and the soccer field

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∵ a/sin(A) = b/sin(B) = c/sin(C)

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4 0
3 years ago
1/5(2x-10)+4x=-3(1/5x+4)
borishaifa [10]
First solve to your equation by step by step.

1/5(2x-10)+4x=-3(1/5x+4)
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Answer is x=-2

It will help you.
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