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Vladimir [108]
3 years ago
13

That's not an answer for me

Mathematics
2 answers:
Viefleur [7K]3 years ago
8 0

Answer:

child anywaysssss

Step-by-step explanation:

yfgxgx

Alik [6]3 years ago
3 0

Answer:

so you need a answer or a question

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Which of the following numbers is less than 2/3? <br> F. -1/2<br> G. 1/3 <br> H. -7/8 <br> J. -1/6
stiks02 [169]

Answer:

All of them are.

Step-by-step explanation:

F. H. J. are all negative and G. is just smaller than 2/3

4 0
3 years ago
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Simpson deposits $1,200 in a savings account that earns simple interest at the rate of 5% per year. What interest does he earn a
Vesnalui [34]

Answer:

1,260

Step-by-step explanation:

5 0
3 years ago
NO LINKS!!! Please help fill in the blanks. Part 11a
Lorico [155]

Answer:

  see attached

Step-by-step explanation:

Here's your worksheet with the blanks filled.

__

Of course, you know these log relations:

  log(a^b) = b·log(a) . . . . . power property

  log(a/b) = log(a) -log(b) . . . . . quotient property

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4 0
2 years ago
Let C(x) be the cost to produce x batches of​ widgets, and let R(x) be the revenue in thousands of dollars. R(x) = − x² + 6x​, C
Musya8 [376]

Answer:

Step-by-step explanation:

Let C(x) be the cost to produce x batches of​ widgets, and let R(x) be the revenue in thousands of dollars.

R(x) = -x^2 + 6x,\\ C(x) = x + 4.

Profit function = Revenue  - cost

So we get profit function by subtracting C(x) from R(x) using algebraic method of subtraction.

Profit function of x

= Pr(x) = R(x) -C(x)\\= -x^2+6x-x-4\\=-x^2+5x-4

7 0
3 years ago
In the context of relationship between variables, increases in the values of one variable are accompanied by increases in the va
garik1379 [7]

Answer:

A. Positive linear.

Step-by-step explanation:

We have that both variables increases, then we have a positive relation. A curvilinear option can not be possible because with this option in some regions could happen that when one variable increases the other one decreases. The negative linear relation can no be because with this option when one variable increases the other decreases. A non linear option is the same as a curvilinear option then can not be possible. Then the best option is a positive linear relationship.

7 0
3 years ago
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