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Alisiya [41]
3 years ago
12

which of the points (s,t) is inside the shaded region of the set of inequalities qualities shown below?

Mathematics
1 answer:
gogolik [260]3 years ago
5 0

Answer:

Step-by-step explanation:

A looks good

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Samuel has a collection of toy cars. His favorites are the 27 red ones, which make up 90% of his collection. How many toy cars d
Damm [24]

Answer:

30

Step-by-step explanation:

5 0
3 years ago
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If f(x) = -7x + 1 and g(x) = Square root of x-5,<br> what is (fºg)(41)?
Ghella [55]

This is similar to the other question you posted. Follow the same steps as before.

First find g(41).

g(41) = sqrt{x - 5}

g(41) = sqrt{41 - 5}

g(41) = sqrt{36}

g(41) = 6

We now find f(6).

f(6) = -7(6) + 1

f(6) = -42 + 1

f(6) = -41

Answer:

(fºg)(41) = -41

Did you follow?

6 0
3 years ago
Mary spent half of her allowance going to the movies . She washed the family car and earned seven dollars . What is her weekly a
Debora [2.8K]
If Mary spent half of her allowance the equation will begin with 1/2x or 0.5x where x is her allowance and 0.5 is half of her allowance spent. Mary also earned 7 dollars by washing the car so this will be added to her allowance spent.
The problem says that after Mary has spent half of her allowance at the movies she was left with 18 dollars so that means that the equation must be equal to 18.

The equation you want to set up is

0.5x+7=18
Where, 18-7=11
0.5x=11
11/.5 = x
x = $22

Thus, Mary has a weekly allowance of 22 dollars.
4 0
2 years ago
If there are 52 cards in a deck with four suits (hearts, clubs, diamonds, and spades), how many ways can you select 5 diamonds a
Luba_88 [7]

Answer:

12C5 *(12C3) = 792*220 =174240 ways

Step-by-step explanation:

For this case we know that we have 12 cards of each denomination (hearts, diamonds, clubs and spades) because 12*4= 52

First let's find the number of ways in order to select 5 diamonds. We can use the combinatory formula since the order for this case no matter. The general formula for combinatory is given by:

nCx = \frac{n!}{x! (n-x)!}

So then 12 C5 would be equal to:

12C5 = \frac{12!}{5! (12-5)!}=\frac{12!}{5! 7!} = \frac{12*11*10*9*8*7!}{5! 7!}= \frac{12*11*10*9*8}{5*4*3*2*1}=792

So we have 792 was in order to select 5 diamonds from the total of 12

Now in order to select 3 clubs from the total of 12 we have the following number of ways:

12C3 = \frac{12!}{3! 9!}=\frac{12*11*10*9!}{3! 9!} =\frac{12*11*10}{3*2*1}=220

So then the numbers of ways in order to select 5 diamonds and 3 clubs are:

(12C5)*(12C3) = 792*220 =174240 ways

3 0
3 years ago
3/7 / 3 in simplest form
vovangra [49]

Answer:

3/7^3

Mark Brainliest

3 0
3 years ago
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