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3 years ago

Correct answers only please!!

Mathematics

1 answer:

Burka [1]3 years ago

7 0

Answer:

Step-by-step explanation:

The distance between points A and B is 7.

Have a great day! :)

and can I please have brainliest?

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75bdivided by 230 need this answer to

hammer [34]

Answer:

0.32608696

Step-by-step explanation:

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3 years ago

Your friend asked you to bring a couple of bags of chips to his party. there are several brands of chips,each a different size a

Lera25 [3.4K]

Your friend asked you to bring a couple of bags of chips to his party. there are several brands of chips, each a different size and price. Write a formula that will help you find the price per gram for each bag.

x= price of bag of chips

y= number of grams

z=price per gram

$z= \frac{x}{y}$

Hope this helps!

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3 years ago

Find the area of the kite.

stich3 [128]

Answer:

18m I guess

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

A 500500-gallon tank initially contains 200200 gallons of brine containing 100100 pounds of dissolved salt. brine containing 11

mixer [17]

Let $A(t)$ denote the amount of salt in the tank at time $t$ . We're given that the tank initially holds $A(0)=100$ lbs of salt.

The rate at which salt flows in and out of the tank is given by the relation

$\dfrac{\mathrm dA}{\mathrm dt}=\underbrace{\dfrac{11\text{ lb}}{1\text{ gal}}\times\dfrac{44\text{ gal}}{1\text{ min}}}_{\text{rate in}}-\underbrace{\dfrac{A(t)}{200+(44-11)t}\times\dfrac{11\text{ gal}}{1\text{ min}}}_{\text{rate out}}$
$\implies A'(t)+\dfrac{11}{200+33t}A(t)=484$

Find the integrating factor:

$\mu(t)=\exp\left(\displaystyle\int\frac{11}{200+33t}\,\mathrm dt\right)=(200+33t)^{1/3}$

Distribute $\mu(t)$ along both sides of the ODE:

$(200+33t)^{1/3}A'(t)+11(200+33t)^{-2/3}A(t)=484(200+33t)^{-1/3}$
$\bigg((200+33t)^{1/3}A(t)\bigg)'=484(200+33t)^{-1/3}$
$A(t)=484\displaystyle\int(200+33t)^{-1/3}\,\mathrm dt$
$A(t)=22(200+33t)^{2/3}+C$

Since $A(0)=100$ , we get

$100=22(200)^{2/3}+C\implies C\approx-652.39$

so that the particular solution for $A(t)$ is

$A(t)=22(200+33t)^{2/3}-652.39$

The tank becomes full when the volume of solution in the tank at time $t$ is the same as the total volume of the tank:

$200+(44-11)t=500\implies 33t=300\implies t\approx9.09$

at which point the amount of salt in the solution would be

$A(9.09)\approx733.47\text{ lb}$

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3 years ago

A point on the circumference of the circle with the equation (x+10)^(2)+(y+1)^(2)=25 is?

svetoff [14.1K]

Answer:

(-5, -1)

(-10, 4)

(-15, -1)

(-10, -6)

Step-by-step explanation:

yeah-ya.......... right?

3 0

3 years ago