Help with what? there isn’t anything there
Hi there!

We can see this by writing the factors as multipliers. We get the following:


Now we can see that the terms that are in common are 3 and a, and therefore we can bring those outside the parenthesis.
The algebraic expression you would write is 12v
Let

. Then

. By convention, every non-zero integer

divides 0, so

.
Suppose this relation holds for

, i.e.

. We then hope to show it must also hold for

.
You have

We assumed that

, and it's clear that

because

is a multiple of 3. This means the remainder upon divides

must be 0, and therefore the relation holds for

. This proves the statement.
26x^2+16x
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