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8090 [49]
4 years ago
12

X+3.8=5.73 what does x equal

Mathematics
2 answers:
Iteru [2.4K]4 years ago
4 0

Answer:

1.93

Step-by-step explanation:

Lelu [443]4 years ago
3 0

Answer:

1.93

Step-by-step explanation:

5.71 - 3.8 = 1.93

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3(x-6)-8x=-2 + 5(2x+1)
postnew [5]

Answer:

<u>x = -1</u>

Step-by-step explanation:

3(x - 6) - 8x = -2 + 5(2x + 1)

3x - 18 - 8x = -2 + 10x + 5

-5x - 18 = 10x + 3

-15x = 15

<u>x = -1</u>

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3 years ago
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What is the volume of a cube whose edges each have a measure of 1.8 inches?
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The answer is 5.832 in


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(3x^5 + x^3 - 4) divided by (x - 2)​
snow_tiger [21]

Answer:

Step-by-step explanation:

8 0
3 years ago
Transform x2 + 6x + 8 = 0 into the form (x − p)2 = q?
liraira [26]
So hmmm x²+6x+8=0

alrite.. let's do some grouping now
( x² + 6x + [?]²) + 8 = 0

notice above, we have a missing fellow in order to get a perfect square trinomial... hmm who would that be?

let's take a peek at the middle guy of the trinomial.. 6x.. hmmm let's factor it, 2*3*x, wait a minute!  2 * 3 * x... we already have x² on the left-side, since the middle term is just 2 * the square root of the other two terms, that means that the guy on the right, our missing guy must be "3"

alrite, let's add 3² then, however, bear in mind that, all we're doing is borrowing from our very good friend Mr Zero, 0

so if we add 3², we also have to subtract 3², let's do so

(x² + 6x +3² - 3²) + 8 = 0

(x² + 6x +3²) + 8 - 3² = 0

(x+3)²=3² - 8

(x+3)² = 1
5 0
4 years ago
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PLEASE HELP!!! Two towns are 1100 miles apart. A group of hikers starts from each town and walks down the trail toward each othe
Vinvika [58]

Answer:

2.54 miles/hr

2.04 miles/hr

Step-by-step explanation:

<u>Given: </u> Distance between the two towns = 1100 miles

Difference between speeds = \frac{1}{2} miles/hr

Total time when they meet = 240 hours

<u>To find:</u>

Let distance traveled by first group = x miles.

Now, the distance traveled by second group = (1100-x) miles/hr

The relation between Speed, Time and Distance is given as:

\text{Speed =} \dfrac{\text{Distance}}{\text{Time}}

Let speed of first group = S_1

S_1 = \dfrac{x}{240}

Let speed of second group = S_2

S_2 = \dfrac{1100-x}{240}

As per question, S_1 = S_2 + \frac{1}{2}

\dfrac{x}{240} = \dfrac{1100-x}{240} + \dfrac{1}{2}\\\Rightarrow \dfrac{x}{240} - \dfrac{1100-x}{240} = \dfrac{1}{2}\\\Rightarrow \dfrac{x-1100+x}{240} = \dfrac{1}{2}\\\Rightarrow 2x - 1100 = 120\\\Rightarrow 2x = 1220\\\Rightarrow x = 610 ft

Now,

S_1 = \dfrac{x}{240}

Putting value of x:

S_1 = \dfrac{610}{240}\\\Rightarrow S_1 = 2.54\ miles/hr

Similarly, putting value of x in S_2:

S_2 = \dfrac{1100-610}{240}\\\Rightarrow S_2=\dfrac{490}{240}\\\Rightarrow S_2 = 2.04\ miles/hr

8 0
3 years ago
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