3/5 is the lowest term. 3/5 = 15/25. Does this help?
6x + 4x + 10 = 180
10x = 170
x = 17
mCA = 4(17) + 10 = 68 + 10 = 78
Answer:
mCA = 78°
a) You are told the function is quadratic, so you can write cost (c) in terms of speed (s) as
... c = k·s² + m·s + n
Filling in the given values gives three equations in k, m, and n.

Subtracting each equation from the one after gives

Subtracting the first of these equations from the second gives

Using the next previous equation, we can find m.

Then from the first equation
[tex]28=100\cdot 0.01+10\cdot (-1)+n\\\\n=37[tex]
There are a variety of other ways the equation can be found or the system of equations solved. Any way you do it, you should end with
... c = 0.01s² - s + 37
b) At 150 kph, the cost is predicted to be
... c = 0.01·150² -150 +37 = 112 . . . cents/km
c) The graph shows you need to maintain speed between 40 and 60 kph to keep cost at or below 13 cents/km.
d) The graph has a minimum at 12 cents per km. This model predicts it is not possible to spend only 10 cents per km.
Which one is prime number 2, 3, 5, 7, 13, 14, 15, 23, 25, 29, 30, 36, 61
soldier1979 [14.2K]
2,3,5,7,13,15,23,and 61 are all prime
The first two pairs.. just substitute the x-coordinate and find y