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STatiana [176]
2 years ago
6

a.When the numerator and the denominator have no common factor other than 1; he fraction is either a proper fraction or mixed nu

mber
Mathematics
1 answer:
tekilochka [14]2 years ago
3 0

Answer:

The fraction is a proper fraction (and irreducible)

Step-by-step explanation:

Given

x = Numerator

y = Denominator

Common\ factor = 1

Required

The type of fraction

A fraction with the given features is a proper fraction and cannot be further reduced.

Take for instance:

x = 2

y = 7

The only common factor between 2\ and\ 7 is 1

\frac{x}{y} = \frac{2}{7}

See that 2/7 is a proper fraction and also 2/7 cannot be reduced (simplified)

<em>The above logic is applicable to all fraction that have the attribute stated in the question (e.g. 3/7, 3/8, 4/9, 7/10, etc.)</em>

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Perform the following division. Show the multiplication you would do to make the divisor a whole number. Round the answer to thr
Luba_88 [7]

Answer:

1.) divisor multiplied by the proper power of ten = 131

2.) dividend multiplied by the proper power of ten =  47

3.) quotient = 2.787

Step-by-step explanation:

1. To make the divisor a whole number you should multiply it by 10^{2} = 100

And the divisor and the dividend must be multiplied by the same power of ten, that is 10^{2} = 100.

So, multiplyind the divisor by 10^{2} = 100:

1.31*100=131

And multiplyind the dividend by 10^{2} = 100:

0.47*100=47

2. Obtain the quotient:

Using the calculator you obtain the quotient between divisor and dividend:

\frac{131}{47}=2.787

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3 years ago
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Galina-37 [17]
The answer is .1599 just cross cancel to find answer.
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Answer:

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Step-by-step explanation:

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so, how to turn our 5 to 15? well, 3*5, thus

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usually, when we get the roots, or zeros, if any common factor that is a constant is about, they get in a division with 0 and get tossed, and aren't part of the roots, thus, we can simply add one, in this case, the common factor of 3, to make the 5 turn to 15
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The symbol between the segments (ll) is of two parallel lines, so it's stating that the segments are parallel.
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