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3 years ago

Darla has three buckets shaped like cylinders. She is filling the buckets

Mathematics

2 answers:

seraphim [82]3 years ago

5 0

Answer:

9 scoops

Step-by-step explanation:

9 scoops is the correct ans 100% sure

(hope this helps can i plz have brainlist :D hehe)

Tanya [424]3 years ago

3 0

Answer:

Step-by-step explanation:

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Let us suppose we have data on the absorbency of paper towels that were produced by two different manufacturing processes. From

maksim [4K]

Answer:

The 95% CI for the difference of means is:

$-155.45 \leq \mu_1-\mu_2 \leq -44.55$

Step-by-step explanation:

The question is incomplete:

"Find a 95% confidence interval on the difference of the towels mean absorbency produced by the two processes. Assumed that the standard deviations are estimated from the data. Round to two decimals places."

Process 1:

- Sample size: 10

- Mean: 200

- S.D.: 15

Process 2:

- Sample size: 4

- Mean: 300

- S.D.: 50

The difference of the sample means is:

$M_d=M_1-M_2=200-300=-100$

The standard deviation can be estimated as:

$\sigma_d=\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}\\\\\sigma_d=\sqrt{\frac{15^2}{10}+\frac{50^2}{4}} =\sqrt{22.5+625}=\sqrt{647.5}=25.45$

The degrees of freedom are:

$df=n_1+n_2-2=10+4-2=12$

The t-value for a 95% confidence interval and 12 degrees of freedom is t=±2.179.

Then, the confidence interval can be written as:

$M_d-t\cdot \sigma_d\leq \mu_1-\mu_2 \leq M_d+t\cdot \sigma_d\\\\-100-2.179*25.45\leq \mu_1-\mu_2 \leq -100+2.179*25.45\\\\-100-55.45 \leq \mu_1-\mu_2 \leq -100+55.45\\\\ -155.45 \leq \mu_1-\mu_2 \leq -44.55$

8 0

3 years ago

You buy magazines for $5 and books for $10. You spent a total of $100. Let x represent the number of magazines and y represent t

bagirrra123 [75]

The answer would be 10x+5y=100

8 0

2 years ago

7. What percent is 6 of 25?

ololo11 [35]

Answer:

6% of 25=1.5

6/100 x 25=1.5

5 0

3 years ago

According to a survey by the National Center for Health Statistics, the heights of adult men in the U.S. are normally distribute

fiasKO [112]

Answer:

0.0151 is the probability that adult men are at most 59 inches or at least 74 inches.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 68 inches

Standard Deviation, σ = 2.75 inches

We are given that the distribution of heights of adult men is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(height between 59 and 74)

$P(59 \leq x \leq 74) = P(\displaystyle\frac{59 - 68}{2.75} \leq z \leq \displaystyle\frac{74-68}{2.75}) = P(-3.2727 \leq z \leq 2.1818)\\\\= P(z \leq 2.1818) - P(z < -3.2727)\\= 0.9854 - 0.0005=98.49\%$

$P(x\leq59 \cup x\geq 74)=1 - P(59\leq x \leq 74) \\=1 - 0.9849\\=0.0151\\=1.51\%$

0.0151 is the probability that adult men are at most 59 inches or at least 74 inches.

8 0

2 years ago

Simplify 1/5 / 1/4 this is how the question is. i don't understand it.

Rzqust [24]

Answer:

The question for you is 1/5 divided by(/) 1/4

The answer!:

4/5

Simplified answer:

3/10

7 0

2 years ago