The solution to these equations is either x < 0 or x > 3.
In order to find them, we need to solve each equation separately. Let's start with the first one.
2x - 1 < -1 -----> Add 1 to both sides
2x < 0 -----> Now divide each side by 2.
x < 0
Now let's look at the second one.
-4x < -12 ----> Divide both sides by -4
x > 3 (Notice that the sign changes direction because we divided by a negative)
When you have an "or" statement, you'll wind up with two answers, so we use both of these.
Answer:
B
Step-by-step explanation:
To factor (q+3)(q+6)
q^2+6q+3q+18
q^2+9q+18
(q+9)(q+2)
3/4(1/2x + 4) + 1/2(x − 1)
First use distributive property to remove the parentheses:
3/8x + 3 + 1/2x -1/2
Now combine like terms:
7/8x + 2 1/2
