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soldier1979 [14.2K]
3 years ago
10

Solve for X B. X X 152

Mathematics
1 answer:
krok68 [10]3 years ago
3 0

Answer:

Step-by-step explanation:

180 - 152 = 28

2x + 28 = 180

2x = 152

x = 76

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A PE teacher is charting the weight and BMI of her students. The table below shows the measured weight for all of her students f
svetlana [45]

Answer:

122.67 average

Step-by-step explanation:

Mean = (every value added up)/(# of values)

Mean = (105 + 2(110) + 2(112) + 3(113) + 2(115) + 5(116) + 4(117) + 7(118) + 5(120) + 5(121) + 4(125) + 5(126) + 2(128) + 130 + 3(132) + 134 + 3(135) + 2(140) + 2(141) + 150)/60

= 7360/60

= 122.67

I had trouble understanding the data but I hope I did this right!

6 0
3 years ago
Please answer this question ASAP
Vilka [71]

Answer:

First, second, third, and fourth are functions

Step-by-step explanation:

Each input in the first, second, third, and fourth only have one output. In the fifth one 3.3 and 6.6 are seen twice as the x-value, so this is incorrect.

(answered this on your other question, but I will put it here too!)

Cada entrada en la primera, segunda, tercera y cuarta tiene solo una salida. En el quinto, 3.3 y 6.6 se ven dos veces como el valor de x, por lo que esto es incorrecto.

(respondí esto en tu otra pregunta, ¡pero también lo pondré aquí!)

3 0
2 years ago
Two numbers have a sum of 1,212 and a difference of 518. What are the two numbers?
guapka [62]

Answer:

The two numbers are

518

694

Step-by-step explanation:

As per requirements the two equations will be

X+Y=1212

X-Y=518

When we subtract these equations we get

X=1212-518

X=694

Now put the X value and find the Y value in any equation

X+Y= 1212

Y=1212-X

Where X = 694

Y=1212-694

Y=518

X=694 and Y=518

4 0
3 years ago
What is the sum of the first 70 consecutive odd numbers? Explain.
expeople1 [14]

The sum of the first n odd numbers is n squared! So, the short answer is that the sum of the first 70 odd numbers is 70 squared, i.e. 4900.

Allow me to prove the result: odd numbers come in the form 2n-1, because 2n is always even, and the number immediately before an even number is always odd.

So, if we sum the first N odd numbers, we have

\displaystyle \sum_{i=1}^N 2i-1 = 2\sum_{i=1}^N i - \sum_{i=1}^N 1

The first sum is the sum of all integers from 1 to N, which is N(N+1)/2. We want twice this sum, so we have

\displaystyle 2\sum_{i=1}^N i = 2\cdot\dfrac{N(N+1)}{2}=N(N+1)

The second sum is simply the sum of N ones:

\underbrace{1+1+1\ldots+1}_{N\text{ times}}=N

So, the final result is

\displaystyle \sum_{i=1}^N 2i-1 = 2\sum_{i=1}^N i - \sum_{i=1}^N 1 = N(N+1)-N = N^2+N-N = N^2

which ends the proof.

5 0
2 years ago
A corner of a rectangle is cut, creating a trapezoid.
dlinn [17]
The sum of a trapezoid is 360 degrees

45+90+90+x=360
45+180+x=360
225+x=360
x=135
5 0
3 years ago
Read 2 more answers
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