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Artyom0805 [142]
3 years ago
5

Electromagnetic quiz, need help with this one*

Physics
1 answer:
oee [108]3 years ago
8 0

Answer:

D

Explanation:

They all decrease when it is farther away

Hope this helps

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While goofing off at the ice skating rink, a student takes off her shoes and places each of them on the ice. Her friend, a hocke
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Answer:

The right shoe

Explanation:

Both shoes have the same speed.

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4 years ago
Which statements describe processes involved in the accretion of planetesimals and protoplanets? Check all that apply.
MakcuM [25]

Answer:

The correct options are;

Both involve the formation of solid particles from nebular materials

Both involve the work of gravitational push on nebular materials

Explanation:

Planetesimals are thought to be the product of grains of cosmic dusts that are found in the debris and protoplanetary discs, such that hundreds of planet forming embrayos are considered to be the result of the collisions of planetesimals that collide with each other to form larger embrayos

Protoplanets is a large planetary body with a stratified interior due to internal melting that has taken place. They originate in the protoplanetary discs from the collision of planetesimals that are up to a kilometer in size.

4 0
3 years ago
Read 2 more answers
En una fundición hay un horno eléctrico con capacidad para fundir totalmente 540 kg de cobre. Si la temperatura inicial del cobr
11Alexandr11 [23.1K]

Answer:

Q = 2.95*10^5 kJ

Explanation:

In order to calculate the energy required to melt the cooper, you first calculate the energy required to reach the boiling temperature. You use the following formula:

Q_1=mc(T_b-T_1)     (1)

m: mass of cooper = 540 kg

c: specific heat of cooper = 390 J/kg°C

Tb: boiling temperature of cooper = 1080°C

T1: initial temperature of cooper = 20°C

You replace the values of the parameters in the equation (1):

Q_1=(540kg)(390\frac{J}{kg.\°C})(1080\°C-20\°C)=2.23*10^8J

Next, you calculate the energy required to melt the cooper by using the following formula:

Q_2=mL_f         (2)

Lf: melting constant of cooper = 134000J/kg

Q_2=(540kg)(134000\frac{J}{kg})=7.24*10^7J

Finally, the total amount of energy required to melt the cooper from a temperature of 20°C is the sum of Q1 and Q2:

Q=Q_1+Q_2=2.23*10^8J+7.24*10^7J=2.95*10^8J=2.95*10^5kJ

The total energy required is 2.95*10^5 kJ

3 0
4 years ago
Davahl is interested in tortoises because they can live for over a hundred years and have unique metabolisms. She wants to perfo
lesya [120]
I would say its time
4 0
3 years ago
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A rock hits the ground with a speed of 7 m/s and a kinetic energy of 100 J. What is the rock's mass?
ad-work [718]
Mass = (2*KE) / v²
∴ the answer is 200/49 
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3 years ago
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